Answer:
a) 
and 
b) t = γt', so it is 8.35 s.
Explanation:
a) The equation of Lorentz transformations is given by:
x' and t' are the position and time in the moving system of reference, and u is the speed of the space ship. x is related to the observer reference.
- x' = 0
- t' = 5.00 s
- u =0.800 c, c is the speed of light 3*10⁸ m/s
Now, to find t we apply the same analysis:
but as x'=0 we just have:
b) Here, Mavis reads 5 s on her watch and Stanley measured the events at a time affected by the Lorentz factor, in other words t = γt', if we see it is the same a) part. So the time interval will be equal to 8.35 s.
I hope it helps you!
Answer:
Besides sound and radio waves, the Doppler effect also affects the light emitted by other bodies in space. If a body in space is "blue shifted," its light waves are compacted and it is coming towards us. If it is "red shifted" the light waves are spread apart, and it is traveling away from us.
Explanation:
Answer:
Charge density on the sphere = 2.2 × 10⁻⁸ C/m²
Explanation:
Given:
Radius of sphere (r) = 12 cm = 0.12 m
Distance from the electric field R = 24 cm = 0.24 m
Magnitude (E) = 640 N/C
Find:
Charge density on the sphere
Computation:
Charge on the sphere (q) = (1/K)ER² (K = 9 × 10⁹)
Charge on the sphere (q) = [1/(9 × 10⁹)](640)(0.24)²
Charge on the sphere (q) = 4 × 10⁻⁹ C
Charge density on the sphere = q / [4πr²]
Charge density on the sphere = [4 × 10⁻⁹] / [4(3.14)(0.12)²]
Charge density on the sphere = [4 × 10⁻⁹] / [0.18]
Charge density on the sphere = 2.2 × 10⁻⁸ C/m²
Answer: (1) 3.83x10^3 J
Explanation:
(1) Fx=(255N)cos60°
dx=30.0m
w=Fx dx =(255)(cos60°)(30.0m)
Gravity only determines the path in projectile motion
