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Anvisha [2.4K]
3 years ago
13

A skateboarder starting from rest accelerates down a ramp at 2 m/s for 2 s. What is the final speed of the skateboarder?

Physics
1 answer:
AlekseyPX3 years ago
8 0

Answer: 4m/s

Explanation:

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The equation of the motion of this object is  \mathbf{y = 3 cos \Big [ \dfrac{ \pi}{2}(t -2) \Big ] }

<h3>What is oscillation?</h3>

An oscillation in a waveform is a periodic set of vibrations an object in the medium produces.

From  the parameters given:

  • The spring is pulled 3 feet down ward from the origin(equilibrium position) = -3
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The angular velocity can be computed by using the formula:

\mathbf{\omega = \dfrac{2 \pi}{T}}

\mathbf{\omega = \dfrac{2 \pi}{4.0}}

The amplitude A from the oscillation is:

\mathbf{\Big|A \Big| = \Big|\dfrac{3 - (-3)}{2} \Big| = 3}

It implies that the vertical shift (D) is:

\mathbf{\dfrac{minimum + maximum}{2} = \dfrac{3+(-3)}{2} = 0}

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\mathbf{y = A cos \Big [ \dfrac{2 \pi}{4}(t -2) \Big ] + 0}

\mathbf{y = 3 cos \Big [ \dfrac{ \pi}{2}(t -2) \Big ] }

Learn more about oscillation in waveform here:

brainly.com/question/15701473

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