The candle flame releases hot gases, which directly go in upwards directions. Due to which the air near the flame of the candle is very hot and dense. The particles along with vapour move up. And since the sideways, the air is not very dense and hot, we are able to hold the candle. In anti-gravity region, there will be no density differences and also, the convection process wont occur. So, the candle quickly snuffs off.
Answer:
I think it will back towards the earth because earth gravitional field will attract to Wards
Search on google. It will have the right answer
Electrons in the outermost shell available for bonding.
The equation of the motion of this object is ![\mathbf{y = 3 cos \Big [ \dfrac{ \pi}{2}(t -2) \Big ] }](https://tex.z-dn.net/?f=%5Cmathbf%7By%20%3D%203%20cos%20%5CBig%20%5B%20%5Cdfrac%7B%20%5Cpi%7D%7B2%7D%28t%20-2%29%20%5CBig%20%5D%20%7D)
<h3>What is oscillation?</h3>
An oscillation in a waveform is a periodic set of vibrations an object in the medium produces.
From the parameters given:
- The spring is pulled 3 feet down ward from the origin(equilibrium position) = -3
- Time to complete one oscillation = 4 seconds
The angular velocity can be computed by using the formula:


The amplitude A from the oscillation is:

It implies that the vertical shift (D) is:

However, by using the formula of the general form of a sinusoidal equation, we have:
![\mathbf{y = A cos \Big [ \dfrac{2 \pi}{4}(t -2) \Big ] + 0}](https://tex.z-dn.net/?f=%5Cmathbf%7By%20%3D%20A%20cos%20%5CBig%20%5B%20%5Cdfrac%7B2%20%5Cpi%7D%7B4%7D%28t%20-2%29%20%5CBig%20%5D%20%2B%200%7D)
![\mathbf{y = 3 cos \Big [ \dfrac{ \pi}{2}(t -2) \Big ] }](https://tex.z-dn.net/?f=%5Cmathbf%7By%20%3D%203%20cos%20%5CBig%20%5B%20%5Cdfrac%7B%20%5Cpi%7D%7B2%7D%28t%20-2%29%20%5CBig%20%5D%20%7D)
Learn more about oscillation in waveform here:
brainly.com/question/15701473