It would be mol/dm^3
Formula of concentration: (no. of moles/volume of solution in dm^3)
1 cm^3 = 0.001dm^3
Hope this helped. :)
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Answer:</h3>
28.17 %
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Explanation:</h3>
In the question we are required to determine the percent by mass of nitrogen in (NH₄)₃PO₄.
- To calculate the percent by mass of an element in a compound we use the formula;
- % by mass =(Mass of the element÷ Relative formula mass of the compound)100
In this case;
- Atomic mass of nitrogen is 14.0 g/mol
But; There are three nitrogen atoms in (NH₄)₃PO₄.
Therefore; Mass of nitrogen in (NH₄)₃PO₄ = 14.0 × 3
= 42 g
The relative formula mass of (NH₄)₃PO₄ = 149.0867 g/mol
Thus;
% by mass of N = (42 g ÷ 149.0867 g/mo)× 100%
= 28.17 %
Therefore, the % by mass of N is (NH₄)₃PO₄ is 28.17%
B= 1s, 2s, 2p I'm pretty sure
About 60 to 64 because 833/13=64
None Do. These are all skeleton equations that must first be balances by adding coeffecients.
Also, CuSO4 + Zn -> ZnCl2 + Cu has different products in terms of elements than its reactants...
