Multiply the percentage by the mass for both and add them to get 63.545 amu
Answer:
146.3g NaCl (mol NaCl/58.44g NaCl) = 2.50 mol NaCl
1.5M NaCl = 1.5 mol NaCl / 1 L = 2.5 mol NaCl / x L, solve for x
x L = 2.5 mol NaCl / 1.5 mol NaCl = 1.66 L
It gives the answer and all the working.
To put it another way:
Dividing the amount required by the molar mass
we quickly see that 2.5 moles are required.
One litre of 1.5 molar solution gives 1.5 moles
we need a further mole, which is 2/3 of 1.5 so 2/3 of a litre.
Answer:
51.53 grams .
Explanation:
Na₃PO₄ ⇄ 3Na⁺¹ + PO₄⁻³ .
1 mole 3 mole
725 mL of 1.3 M Na⁺ ions
= .725 x 1.3 moles of Na⁺ ions
= .9425 moles
3 mole of Na⁺ is formed by 1 mole of Na₃PO₄
.9425 mole of Na⁺ is formed by .9425/3 mole of Na₃PO₄
Na₃PO₄ needed = .9425/3 moles = .3142 moles
Molecular weight of Na₃PO₄ = 164
grams of Na₃PO₄ needed = .3142 x 164 = 51.53 grams .
Answer:
Super-heavy elements like 114 usually only exist for fractions of a second. ... The physicists called these magic numbers the “island of stability”, because the elements with the numbers cluster together on the periodic table, flanked on all sides by ephemeral elements that dissipate in nanoseconds.
The reaction will shift toward the reactants if the volume is cut in half.
<h3 /><h3>Reactants </h3>
The initial components of a chemical reaction are called reactants. Chemical bonds between reactants are broken and new ones are created in order to create products. Reactants and products are listed on the left and right sides, respectively, of the arrow in a chemical equation.
Substances on both sides of an arrow that points left and right are both reactants and products in a chemical process (the reaction proceeds in both directions simultaneously). A chemical equation that is balanced has the same amount of atoms of each element in the reactants and products. Around 1900–1920 is when the word "reactant" was first used. There are instances when the word "reagent" is interchangeable.
Learn more about reactants here:
brainly.com/question/17096236
#SPJ4