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3 years ago

8

A bag has 12 different-colored marbles: 4 green, 5 blue, 1 yellow, and 2 orange. You draw a marble from the bag. If you get an o

range marble or yellow marble, you win a prize.

1 answer:

Lynna [10]3 years ago

7 0

Answer:

I believe this that it would be 1/3 chances you grab a yellow or a orange

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Solve 12 1/2 - (-41/2) =

madam [21]

Answer:

1/6

Step-by-step explanation:

8 0

3 years ago

Please at least help me cause I have no idea

Blababa [14]

Answer:

Solving the given formula for v2 gives us:

$a(t_2-t_1)+v_1 = v_2$

Step-by-step explanation:

Solving an equation for a particular variable means that the variable has to be isolated on one side of the equation.

Given equation is:

$a = \frac{v_2-v_1}{t_2-t_1}$

Multiplying both sides by t2-t1

$(t_2-t_1) . a = \frac{v_2-v_1}{t_2-t_1} . (t_2-t_1)\\a(t_2-t_1) = v_2-v_1$

Adding v1 to both sides of the equation

$a(t_2-t_1)+v_1 = v_2-v_1+v_1\\a(t_2-t_1)+v_1 = v_2$

Hence,

Solving the given formula for v2 gives us:

$a(t_2-t_1)+v_1 = v_2$

8 0

3 years ago

Two trains leave stations 272 miles apart at the same time. One train travles 75 miles per hour while the other travles at 95 mi

VARVARA [1.3K]

102 miles for them to meet up

5 0

3 years ago

vovikov84 [41]

<h3>Answer to Question 1:</h3>

AB= 24cm

BC = 7cm

<B = 90°

AC = ?

<h3>Using Pythagoras theorem :-</h3>

AC^2 = AB^2 + BC ^ 2

AC^2 = 24^2 + 7^2

AC^2 = 576 + 49

AC^2 = √625

AC = 25

<h3>Answer to Question 2 :-</h3>

sin A = 3/4

CosA = ?

TanA = ?

<h3>SinA = Opp. side/Hypotenuse</h3><h3> = 3/4</h3>

(Construct a triangle right angled at B with one side BC of 3cm and hypotenuse AC of 4cm.)

<h3>Using Pythagoras theorem :-</h3>

AC^2 = AB^2 + BC ^ 2

4² = AB² + 3²

16 = AB + 9

AB = √7cm

<h3>CosA = Adjacent side/Hypotenuse</h3>

= AB/AC

= √7/4

<h3>TanA= Opp. side/Adjacent side</h3>

=BC/AB

= 3/√7

4 0

2 years ago

mina [271]

Answer:

yes

Step-by-step explanation:

i dont know

8 0

2 years ago