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3 years ago

What is the molarity of a solution that contains 14.92 grams magnesium oxide (MgO) in 365ml of solution?

Chemistry

2 answers:

AnnZ [28]3 years ago

6 0

Answer:

Option A. 1.01 molar solution

Explanation:

Step 1:

Data obtained from the question. This include the following:

Mass of MgO = 14.92g

Volume of solution = 365mL

Molarity of solution =.?

Step 2:

Determination of the number of mole present in 14.92g of MgO.

This is illustrated below:

Mass of MgO = 14.92g

Molar mass of MgO = 24.3 + 16 = 40.3g/mol

Number of mole MgO =...?

Mole = Mass /Molar Mass

Number of mole of MgO = 14.92/40.3 = 0.370 mole

Step 3:

Determination of the molarity of the solution.

This can be obtained as follow:

Mole of MgO = 0.370 mole

Volume = 365mL = 365/1000 = 0.365L

Molarity =..?

Molarity = mole /Volume

Molarity = 0.370/0.365

Molarity = 1.01M

Yuki888 [10]3 years ago

3 0

Answer:

a. 1.01 molar solution

Explanation:

Now we have to recall the formula;

n= CV

Where

n= number of moles of magnesium oxide

C= concentration of magnesium oxide solution = ???

V= volume of magnesium oxide solution= 365 ml

But;

n= m/M

Where;

m= given mass of magnesium oxide= 14.2 g

M= molar mass of magnesium oxide= 40.3044 g/mol

Substituting values;

14.2g/40.3044 g/mol = C×365/1000

0.3523= 0.365 C

C= 0.3523/0.365

C= 0.965

C= 1.00 molar (approx)

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Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu

Monica [59]

Answer: The volume of the 1.224 M NaOH solution needed is 26.16 mL

Explanation:

In order to prepare the dilute NaOH solution, solvent is added to a given amount of the NaOH stock solution up to a final volume of 250.0 mL.

Since only solvent is added, the amount of the solute, NaOH, in the dilute solution is the same as in the volume taken from the stock solution.

Molarity (M) is calculated from the following equation:

M = n ÷ V

where n is the number of moles of the solute in the solution, and V is the volume of the solution.

Accordingly, the number of moles of the solute is given by

n = M x V

Now, let's designate the stock NaOH solution and the dilute solution as (1) and (2), respectively . The number of moles of NaOH in each of these solutions is:

n (1) = M (1) x V (1)

n (2) = M (2) x V (2)

As the amount of NaOH in the dilute solution is the same as in the volume taken from the stock solution,

n (1) = n (2)

and

M (1) x V (1) = M (2) x V (2)

For the stock solution, M (1) = 1.244 M, and V (1) is the volume needed. For the dilute solution, M (2) = 0,1281 M, and V (2) = 250.0 mL.

The volume of the stock solution needed, V (1), is calculated as follows:

V (1) = M (2) x V (2) ÷ M (1)

V (1) = 0.1281 M x 250.0 mL ÷ 1.224 M

V (1) = 26.16 mL

The volume of the 1.224 M NaOH solution needed is 26.16 mL.

7 0

3 years ago