Answer:
V=1601gal
Explanation:
Hello! This problem is solved as follows,
First we must raise the equation that defines the pressure at the bottom of the tank with the purpose of finding the height that olive oil reaches.
This is given as the sum due to the atmospheric pressure (1atm = 101.325kPa), and the pressure due to the weight of the olive oil, taking into account the above, the following equation is inferred.
P=Poil+Patm
P=total pressure or absolute pressure=26psi=179213.28Pa
Patm= the atmospheric pressure =101325Pa
Poil=pressure due to the weight of olive oil=0.86αgh
α=density of water=1000kg/m^3
g=gravity=9.81m/s^2
h= height that olive oil reaches
solving
P=Poil+Patm
P=Patm+0.86αgh
[/tex]
Now we can use the equation that defines the volume of a cylinder.
V=
D=3ft=0.9144m
h=9.23m
solving
finally we use conversion factors to find the volume in gallons
Answer:
The appropriate solution is "1481.76 N".
Explanation:
According to the question,
Mass,
m = 540 kg
Coefficient of static friction,
= 0.28
Now,
The applied force will be:
⇒
By substituting the values, we get
Answer:
class helloSarah {
public static void main(String [] args) {
Name = "Hello Sarah";
System.out.print(Name);
}
}
Explanation:
<em>The question seem incomplete; However, since the program is incorrect, I'll assume the question is to correct the given code;</em>
The program segment was written in Java and the correct program is in the answer section
<u>See bold texts for line by line explanation </u>
This line declares the class name
<em>class helloSarah {</em>
This line declares the main method of the program
<em>public static void main(String [] args) {</em>
This line initializes string variable Name
<em>String Name = "Hello Sarah";</em>
This line prints the initialized variable
<em>System.out.print(Name);</em>
<em>}</em>
<em>}</em>
<em />
I think it’s is false I’m not that sure