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Vika [28.1K]
3 years ago
5

(100 POINTS) {BRIANLIEST} PLEASE HELP ME

Engineering
1 answer:
zhuklara [117]3 years ago
6 0

Answer:

I think option d is the answer

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A 60-Hz 3-phase induction motor is required to drive a load at approximately 850 rpm. How many poles should the motor have
Anastaziya [24]

Answer:

8 poles

Explanation:

Given

Frequency, f = 60Hz

Speed, n_s = 850rpm

Required

Calculate the number of poles the motor should have?

To solve this question, we make use of synchronous angular velocity  formula

n_s = \frac{120f}{P}

Where

P = Number\ of\ Poles

Substitute values for n_s and f in n_s = \frac{120f}{P}

850 = \frac{120 * 60}{P}

850 = \frac{7200}{P}

Multiply both sides by P

P * 850 = \frac{7200}{P} * P

P * 850 = 7200

Divide both sides by 850

\frac{P * 850}{850} = \frac{7200}{850}

P = \frac{7200}{850}

P = 8.47058823529

However, the number of poles must be an integer.

So:

P = 8

7 0
3 years ago
Write cout statements with stream manipulators that perform the following:
Semenov [28]

Answer:

A)cout<<setw(9)<<fixed<<setprecision(2)<<34.789;

B)cout<<setw(5)<<fixed<<setprecision(3)<<7.0;

C)cout<<fixed<<5.789E12;

D)cout<<left<<setw(7)<<67;

Explanation:

Stream Manipulators are functions specifically designed to be used in conjunction with the insertion (<<) and extraction (>>) operators on stream objects in C++ programming while the 'cout' statement is used to display the output of a C++to the standard output device.

setw:  used to specify the minimum number of character positions on the output field

setprecision: Sets the decimal precision to be used to format floating-point values on output operations.

fixed:  is used to set the floatfield format flag for the specified str stream.

left: adjust output to the left.

A) To display the number 34.789 in a field of eight spaces with two decimal places of precision. cout<<setw(9)<<fixed<<setprecision(2)<<34.789;

B) To display the number 7.0 in a field of six spaces with three decimal places of precision. cout<<setw(5)<<fixed<<setprecision(3)<<7.0;

C) To print out the number 5.789e+12 in fixed-point notation.  cout<<fixed<<5.789E12;

(D) To display the number 67 left-justified in a field of six spaces. cout<<left<<setw(7)<<67;

7 0
4 years ago
Describe the risks associated with their working environment (such as the tools, materials and equipment that they use, spillage
Llana [10]

The risks which are associated with such working environment and not reporting accidental breakages of tools is pollution and damage to the body system of individuals.

<h3>What is Risk?</h3>

This is defined as the possibility of something causing a bad event to occur and is common in workplace when tools are left carelessly which can cause injuries etc.

In the case of a working environment with oil spills, it can lead to slipping of the individuals present in the area and not reporting accidental breakages of tools or equipment could also lead to pollution and different forms of accident which thereby making it the most appropriate choice in this context.

Read more about Risk here brainly.com/question/1224221

#SPJ1

3 0
2 years ago
TE
Afina-wow [57]

This would be answer choice D: all of the above. Low back pain can be classified by duration as acute (pain lasting less than 6 weeks), sub-chronic (6 to 12 weeks), or chronic (more than 12 weeks).

7 0
3 years ago
A 3.7 g mass is released from rest at C which has a height of 1.1 m above the base of a loop-the-loop and a radius of 0.2 m . Th
Dmitrij [34]

Answer:

Normal force = 0.326N

Explanation:

Given that:

mass released from rest at C = 3.7 g = 3.7 × 10⁻³ kg

height of the mass = 1.1 m

radius = 0.2 m

acceleration due to gravity = 9.8 m/s²

We are to determine the normal force pressing on the track at A.

To to that;

Let consider the conservation of energy relation; which says:

mgh = mgr + 1/2 mv²

gh = gr + 1/2 v²

gh - gr = 1/2v²

g(h-r) = 1/2v²

v² = 2g(h-r)

However; the normal force will result to a centripetal force; as such, using the relation

N =mv²/r

replacing the value for v² = 2g(h-r) in the above relation; we have:

Normal force = 2mg(h-r)/r

Normal force = 2 × 3.7 × 10⁻³ × 9.8 ( 1.1 - 0.2 )/ 0.2

Normal force = 0.065268/0.2

Normal force = 0.32634 N

Normal force = 0.326N

6 0
3 years ago
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