Answer:
Explanation:
E° (calomel electrode) = 0.268 v
E( calomel electrode, 1M KCl) = 0.280 v
For calomel electrode
![E = E^0 _( Hg^+/Hg ) - \frac{.059}{2} \times log( a_{cl^-} )^2](https://tex.z-dn.net/?f=E%20%3D%20E%5E0%20_%28%20Hg%5E%2B%2FHg%20%29%20-%20%5Cfrac%7B.059%7D%7B2%7D%20%5Ctimes%20log%28%20a_%7Bcl%5E-%7D%20%29%5E2)
![.280 = .268 - \frac{.059}{2} \times log( a_{cl^-} )^2](https://tex.z-dn.net/?f=.280%20%3D%20.268%20-%20%5Cfrac%7B.059%7D%7B2%7D%20%5Ctimes%20log%28%20a_%7Bcl%5E-%7D%20%29%5E2)
![.012= - \frac{.059}{2} \times log( a_{cl^-} )^2](https://tex.z-dn.net/?f=.012%3D%20%20-%20%5Cfrac%7B.059%7D%7B2%7D%20%5Ctimes%20log%28%20a_%7Bcl%5E-%7D%20%29%5E2)
![log( a_{cl^-})^2= - .4067](https://tex.z-dn.net/?f=log%28%20a_%7Bcl%5E-%7D%29%5E2%3D%20-%20.4067)
= 0.626 .
1. 80 Kj
2. 120-80= 40 Kj
3. 120-20= 100Kj
4. 20-80= -60Kj
5. +60 Kj
6. Exothermic because 4 is negative
It’s absorbed The outer layer of fabric does get hotter because the black color absorbs more heat. And that heat doesn't get transmitted to the skin because of the thick fabric. But thin black clothing transmits that heat to the skin, making a person hotter
Answer:
<h3>AD=S×AT</h3>
Explanation:
<h3>the question is solving for AD </h3><h3>if s=AD/AT; THEN S/1=AD/AT </h3><h3>by cris cross multiplication </h3><h3>AD=S×AT</h3>