Answer:
773.25 Hz
Explanation:
Concept : In an open organ pipe in fundamental mode of vibration
wave length of wave λ = 2L
where L is length of the pipe
frequency = velocity of sound / λ
Given values: fundamental frequency = 288 Hz
fluid is air. velocity of sound = 340 m/s
⇒ 288 = 340/2L
⇒L = 59.02 cm
The point to be noted is if the pipe is filled with helium initially at the same temperature, there would be change in the sound velocity .Then, frequency of note produced will also be changed .
We know that velocity of sound is inversely proportional to square root of molar mass of gas
velocity of sound in air / velocity of sound in helium = Square root of (Molar mass of Helium/ molar mass of air)
Now, frequency = velocity of sound / λ
= 912.75 / (2 x 0.5902)
= 773.25 Hz
We don't see any circuit diagrams.
This worries us for a few seconds, until we realize that we don't know anything about the experiment described in the problem either, so we don't have to worry about it at all.
Main features of RCCB are:
- Both wires phase and neutral are connected through RCCB.
- Whenever there is any ground fault occurs, then it trips the circuit.
- The number of current supplies through the line should go back through neutral.
- These are a very effective type of shock protection.
Natural was thought to be straight up or straight down and violent was thought to be the result of a push or pull
Answer:
Answer:
71.6°
Explanation:
According to the diagram
ED = 6 feet
DA = EB = 3 feet
AC = 15 feet
AB = ED = 6 feet
BC = AC - AB = 15 - 6 = 9 feet
Let the angle is θ from the horizontal
By the triangle EBC
tanθ = BC / EB = 9 / 3
tanθ = 3
θ = 71.6°
Thus, the angle from the horizontal is 71.6°.
Explanation:
