Answer:
400 mL of 4% salt solution and 600 mL of 16% salt solution need to be mixed
Explanation:
Let's assume concentration of brine salt solutions are in %(w/v) unit.
Final mixture has a concentration of 11.2% salt and volume of 1 L or 1000 mL
Hence, amount of salt in final mixture = 
Suppose x mL of 4% salt solution and (1000-x) mL of 16% salt solution need to be mixed to get final mixture
So, amount of salt in x mL of 4% salt solution = 
amount of salt in x mL of 16% salt solution =
Hence, 
or, 
So, 400 mL of 4% salt solution and 600 mL of 16% salt solution need to be mixed
Maybe u should choose D beacause it makes more sense.
Answer:
Distance from the earth
Explanation: Trust me we just did this and I got 100 percent on all of it.
Answer:
3.18 g of lead sulfate is produced in this reaction
Explanation:
The reaction is this one:
Na₂SO₄ (aq) + Pb(NO₃)₂ (aq) → 2 NaNO₃ (aq) + PbSO₄ (s)
Let's determine the moles of reactants, to find out which is the limiting.
Molarity . volume = Mol
0.105 m/L . 0.100L = 0.0105 moles of sulfate
0.985 m/L . 0.100L = 0.0985 moles of nitrate
Ratio is 1:1, so 1 mol of sulfate needs 1 mol of nitrate, to react.
0.0985 moles of nitrate need 0.0985 moles of sulfate to react, but I only have 0.0105 moles so the sulfate is my limiting reactant.
Ratio is again 1:1, so 0.0105 moles of sulfate make 0.0105 moles of lead sulfate.
Mol . molar mass = mass → 0.0105 mol . 303.26 g/m = 3.18 g