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maksim [4K]
3 years ago
8

Write the isotope notation for an element with 5 protons and 6 neutrons.

Chemistry
1 answer:
Korolek [52]3 years ago
4 0

The isotope notation : \large {{{11} \atop {5}} \right X}

<h3> Further explanation </h3>

Given

53 protons and 20 neutron

Required

The isotope notation

Solution

Isotopes are elements that have the same atomic number with a different mass number

The following element notation,

 \large {{{A} \atop {Z}} \right X}

X = symbol of element

A = mass number

   = number of protons + number of neutrons

Z = atomic number

   = number of protons = number of electrons, on neutral elements

So the mass number of element = 5 + 6 11

Atomic number = 5

The symbol :

\large {{{11} \atop {5}} \right X}

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Answer:

The reaction given is  

Chemistry homework question answer, step 1, image 1

Since in equilibrium constant expression, the concentration of liquid components is not written.

Hence the equilibrium constant expression for the above reaction can be written as  

Chemistry homework question answer, step 1, image 2

where [NO] = equilibrium concentration of NO

[NO2 ] = equilibrium concentration of NO2

[HNO3 ] = equilibrium concentration of HNO3

Step 2

Given : mass of NO at equilibrium = 18.6 g

mass of NO2 at equilibrium = 15.1 g

and mass of HNO3 at equilibrium = 13.1 g

Since molar mass of HNO3 = 63 g/mol, molar mass of NO = 30 g/mol and molar mass of NO2 = 46 g/mol

Hence the moles of gases at equilibrium are

Chemistry homework question answer, step 2, image 1

Step 3

Since mass of solution = mass of HNO3 + mass of water = 13.1 + 234.8 = 247.9 g

Assuming density of solution = density of water = 1.00 g/mL

=> mass of solution = volume of solution X density of solution  

=> 247.9 = 1.00 X volume of solution  

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Explanation:

5 0
3 years ago
On another planet, the isotopes of titanium have the given natural abundances. Isotope Abundance Mass (u) 46Ti 70.600% 45.95263
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<u>Answer:</u> The average atomic mass of element titanium is 46.889 amu.  

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i .....(1)

  • <u>For isotope 1 (Ti-46) :</u>

Mass of isotope 1 = 45.95263 amu

Percentage abundance of isotope 1 = 70.600 %

Fractional abundance of isotope 1 = 0.70600

  • <u>For isotope 2 (Ti-48) :</u>

Mass of isotope 2 = 47.94795 amu

Percentage abundance of isotope 2 = 11.900 %

Fractional abundance of isotope 2 = 0.11900

  • <u>For isotope 3 (Ti-50) :</u>

Mass of isotope 3 = 49.94479 amu

Percentage abundance of isotope 3 = 17.500 %

Fractional abundance of isotope 3 = 0.17500

Putting values in equation 1, we get:

\text{Average atomic mass of titanium}=[(45.95263\times 0.70600)+(47.94795\times 0.11900)+(49.94479\times 0.17500)]

\text{Average atomic mass of titanium}=46.889amu

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4 years ago
Which of the following terms describes carbon tetrachloride?(CCI4)
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Answer:

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Explanation:

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