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Alja [10]
3 years ago
8

6. Given a sheet of metal that is 1.2 cm wide, 3.8 cm long and 1.0 mm thick with a density of 8.57 g/cm3, calculate the mass of

the metal.
Engineering
1 answer:
Jobisdone [24]3 years ago
5 0

Answer:

39.08 or 39.0792

Explanation:

1.2*3.8=4.56 8.57*4.56=39.0792  (Round up is 39.08

Volume: m/v*d (The m over v goes as a fraction and the density is in the middle beside the m over v with a multiplication sign)

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Answer:

N = 38546.82 rpm

Explanation:

D_{1} = 150 mm

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              = 17671.45 mm^{2}

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              = 49087.78 mm^{2}

The centrifugal force acting on the flywheel is fiven by

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Since density, \rho = \frac{M}{V}

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                        M = \rho \times A\times tM = 7100 \times \frac{\pi }{4}\left ( D_{2}^{2}-D_{1}^{2} \right )\times t

                        M = 7100 \times \frac{\pi }{4}\left ( 250^{2}-150^{2} \right )\times 37

                        M = 8252963901

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33618968.38 = 8252963901\times 50\times \omega ^{2}

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\omega = \frac{2\pi N}{60}

4036.61 = \frac{2\pi N}{60}

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