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Alja [10]
3 years ago
8

6. Given a sheet of metal that is 1.2 cm wide, 3.8 cm long and 1.0 mm thick with a density of 8.57 g/cm3, calculate the mass of

the metal.
Engineering
1 answer:
Jobisdone [24]3 years ago
5 0

Answer:

39.08 or 39.0792

Explanation:

1.2*3.8=4.56 8.57*4.56=39.0792  (Round up is 39.08

Volume: m/v*d (The m over v goes as a fraction and the density is in the middle beside the m over v with a multiplication sign)

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Answer:

n=2.32

w= -213.9 KW

Explanation:

V_1=0.3m^3,T_1=298 K

V_2=0.1m^3,T_1=1273 K

Mass of air=1 kg

For polytropic process  pv^n=C ,n is the polytropic constant.

  Tv^{n-1}=C

  T_1v^{n-1}_1=T_2v^{n-1}_2

298\times .3^{n-1}_1=1273\times .1^{n-1}_2

n=2.32

Work in polytropic process given as

       w=\dfrac{P_1V_1-P_2V_2}{n-1}

      w=mR\dfrac{T_1-T_2}{n-1}

Now by putting the values

w=1\times 0.287\dfrac{289-1273}{2.32-1}

w= -213.9 KW

Negative sign indicates that work is given to the system or work is done on the system.

For T_V diagram

  We can easily observe that when piston cylinder reach on new position then volume reduces and temperature increases,so we can say that this is compression process.

5 0
3 years ago
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Answer:

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4 0
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2. BCD uses 6 bits to represent a symbol. a) True b) False​
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Answer:

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Explanation:

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