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Alecsey [184]
3 years ago
15

Water flows down a rectangular channel that is 1.2 m wide and 1 m deep. The flow rate is 0.95 m/s. Estimate the Froude number of

the flow.
Engineering
1 answer:
olga_2 [115]3 years ago
8 0

Answer:

The Froude number of the flow in the channel is 0.253

Explanation:

We know that Froude number for a rectangular channel is given by

F_{r}=\frac{v}{\sqrt{gy}}

where,

v = is the velocity of flow

g = is the acceleration due to gravity

y = depth of flow

We know that velocity is calculated from the flow rate as

v=\frac{Q}{Area}\\\\\therefore v=\frac{0.95}{1.2\times 1}=0.792m/s

Applying the given values in the equation we obtain Froude number as followsHence\\\\F_{r}=\frac{0.792}{\sqrt{9.81\times 1}}=0.253

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The normal stress at gage H calculated in Part 1 includes four components: an axial component due to load P, σaxial, P, a bendin
Degger [83]

Answer:

hello your question has some missing information attached to the answer is the missing component

Answer : αaxial,p = -6.034 ksi ( compressive )

             αbend,p = 19.648 ksi ( tensile )

Explanation:

αaxial, p = \frac{-p}{A}   equation 1

αbend, p = \frac{(P*A)*\frac{d}{2} }{I_{z} } equation 2

P = load = 35 kips

A = area of column = 5.8 in^{2}

d = column cross section depth = 9.5 in

I_{Z} = 55.0 in^{4}

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αaxial,p = -35 / 5.8 = - 6.034 ksi ( compressive )

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αbend, p = \frac{(35*6.5)(\frac{9.2}{2}) }{55} = + 19.648 ksi ( tensile )

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Re armature of a 4 pole DC generator is required to generate an emf of 520v on open circuit when revolving at a speed of 660rpm.
bija089 [108]

Since the armature is wave wound, the magnetic flux per pole is 0.0274 Weber.

<u>Given the following data:</u>

  • Emf = 520 Volts
  • Speed = 660 r.p.m
  • Number of armature conductors = 144 slots
  • Number of poles = 4 poles
  • Number of parallel paths = 2

To find the magnetic flux per pole:

Mathematically, the emf generated by a DC generator is given by the formula;

E = \frac{\theta ZN}{60} × \frac{P}{A}

<u>Where:</u>

  • E is the electromotive force in the DC generator.
  • Z is the total number of armature conductors.
  • N is the speed or armature rotation in r.p.m.
  • P is the number of poles.
  • A is the number of parallel paths in armature.
  • Ф is the magnetic flux.

First of all, we would determine the total number of armature conductors:

Z = 144 × 2 × 3

Z = 864

Substituting the given parameters into the formula, we have;

520 = \frac{\theta (864)(660)}{60} × \frac{4}{2}

520 = \theta (864)(11) × 2

520 = 19008 \theta \\\\\Theta = \frac{520}{19008}

<em>Magnetic flux </em><em>=</em><em> 0.0274 Weber.</em>

Therefore, the magnetic flux per pole is 0.0274 Weber.

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