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wlad13 [49]
2 years ago
8

The A/C compressor will not engage when the A/C is turned on. The static refrigerant pressure is 75 psi and the outside temperat

ure is 72 degrees F. Technician A says that a poor connection at the pressure cycling switch could be the cause. Technician B says that a faulty A/C clutch coil could be the cause. Who is correct
Engineering
1 answer:
VikaD [51]2 years ago
3 0

In the case above,  poor connection at the pressure cycling switch  and also a faulty A/C clutch coil could be the cause.

<h3>What is likely the reason when an A/C compressor will not engage if A/C is turned on?</h3>

The cause that hinders the A/C Compressor from engaging are:

  • Due to low pressure lockout.
  • Due to a poor ground
  • Due to bad clutch coil.
  • Dur to an opening in the wire that links to the clutch coil.
  • Due to a blown fuse.

Note that the pressure switches is known to be one that control the on/off function of any kind of AC compressor and as such, if there is switch failure, it can hinder the AC compressor from functioning at all.

Therefore, technician A and B are correct.

Learn more about refrigerant pressure from

brainly.com/question/10054719

#SPJ1

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Explanation:

Detailed steps are attached below.

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Consider a Mach 4.5 airflow at a pressure of 1.25 atm. We want to slow this flow to a subsonic speed through a system of shock w
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What do you do if building doesn't have enough water pressure for sprinklers? a. Increase pipe size b. Adjust budget to accommod
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Acoke can with inner diameter(di) of 75 mm, and wall thickness (t) of 0.1 mm, has internal pressure (pi) of 150 KPa and is suffe
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Answer:

All 3 principal stress

1. 56.301mpa

2. 28.07mpa

3. 0mpa

Maximum shear stress = 14.116mpa

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di = 75 = 0.075

wall thickness = 0.1 = 0.0001

internal pressure pi = 150 kpa = 150 x 10³

torque t = 100 Nm

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∂1 = 150x10³x0.075/2x0,0001

= 0.5625 = 56.25mpa

∂2 = 150x10³x75/4x0.1

= 28.12mpa

T = 16x100/(πx75x10³)²

∂1,2 = 1/2[(56.25+28.12) ± √(56.25-28.12)² + 4(1.207)²]

= 1/2[84.37±√791.2969+5.827396]

= 1/2[84.37±28.33]

∂1 = 1/2[84.37+28.33]

= 56.301mpa

∂2 = 1/2[84.37-28.33]

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This is a 2 d diagram donut is analyzed in 2 direction.

So ∂3 = 0mpa

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6 0
3 years ago
Consider a system with two tasks, Task1 and Task2. Task1 has a period of 200 ms, and Task2 has a period of 300 ms. All tasks ini
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<u>Explanation:</u>

Task 1 time period = 200ms, Task 2 time period = 300ms

Task ticked = \frac{1000ms}{200ms}= 5  →  5 times

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At 600 ms → 200ms 200ms 200ms

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4 0
3 years ago
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