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2 years ago

8

Mrs. Pena is buying 3 kinds of sandwiches for a family reunion. She buys x egg salad sandwiches at $3.10 each. She buys

1 answer:

iren2701 [21]2 years ago

6 0

The answer is A since there are x egg sandwiches that cost $3.10, y beef that cost $3.35 and z cheese sandwiches that cost $2.85, so buying one more of any of those would mean paying that amount a the number of times you buy it. So 2 of x is $3.10 x 2 = $

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Please answer the question below and show working

strojnjashka [21]

Answer:

i. Slope=-1/6

ii. Midpoint= (1,8.5)

iii. <em>Distance</em><em>=</em><em> </em><em>√</em><em>3</em><em>7</em><em> </em><em>units</em>

<em>iv.</em><em> </em><em> </em><em> </em><em> </em><em>Slope </em><em>of </em><em>t=</em><em>2</em>

<em>please </em><em>see</em><em> the</em><em> attached</em><em> picture</em><em> for</em><em> full</em><em> solution</em><em>.</em><em>.</em><em>.</em>

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6 0

3 years ago

Summation notation of 2+4+6+8+10

Veronika [31]

The answer to this question is 30.

4 0

3 years ago

Help me out plz................................

12345 [234]

I think it is A but make sure with someone else

7 0

2 years ago

Read 2 more answers

Sue is drawing two lines on a coordinate plane. She begins the first line at the origin and ends at (4,3). She begins the 2nd li

ludmilkaskok [199]

Answer:

what is it man

Step-by-step explanation:

im sure u solved it by now

6 0

2 years ago

An arithmetic sequence is defined by the recursive formula t1 = 11, tn = tn - 1 - 13, where n ∈N and n > 1. Which of these is

galben [10]

coolio

$t_1=11$

$t_n=t_{n-1}-13$

so each term is ound by subtracting 13 from the previous term

an aritmetic sequence can be written as

$t_n=t_1+d(n-1)$ were

$t_n$ is the nth term

$t_1$ is the first term

d is common difference, which can also be found by doing $t_n-t_{n-1}=d$

n=wich term

we know that $t_1=11$ and we can find d

$t_n=t_{n-1}-13$ , $t_n-t_{n-1}=-13=d$

so te general term is $t_n=11-13(n-1)$ which can also be expanded and written as $t_n=-13n+24$

6 0

3 years ago