Answer: 3.01 x 10^24 atoms
Explanation:
Based on Avogadro's law:
1 mole of any substance has 6.02 x 10^23 atoms
So, 1 mole of water = 6.02 x 10^23 atoms
5 moles of water = Z atoms
To get the value of Z, cross multiply
Z x 1 mole = (6.02 x 10^23 atoms x 5 moles)
Z•mole = 30.1 x 10^23 atoms•mole
Divide both sides by 1 mole
Z•mole/1 mole = 30.1 x 10^23 atoms•mole/ 1 mole
Z = 30.1 x 10^23 atoms
[Place the value of Z in standard form]
Z = 3.01 x 10^24 atoms
Thus, there are 3.01 x 10^24 atoms in 5 mole of water
B. Because there are 3 molecules in right and 2 molecules in the left, so entropy rises.
Answer:
C. Lose three electrons to have a full outer shell
Explanation:
Al is in Group 13 of the Periodic Table, so it has three valence electrons.
It must either lose three electrons or gain five to achieve a stable octet.
It is easier to lose three electrons than it is to gain five, so Al loses three electrons.
D. is wrong, for the same reason.
A. is wrong. If Al lost three electrons, it would be breaking into a stable inner shell.
C. is wrong. Al is a metal, so it will lose electrons in a reaction.
Answer:
The number of moles of xenon are 1.69 mol.
Explanation:
Given data:
Number of moles of xenon = ?
Volume of gas = 37.8 L
Temperature = 273 K
Pressure = 1 atm
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will put the values in formula.
1 atm × 37.8 L = n × 0.0821 atm.L/ mol.K ×273 K
37.8 atm.L = n × 22.413 atm.L/ mol.
n = 37.8 atm.L / 22.413 atm.L/ mol.
n = 1.69 mol
The number of moles of xenon are 1.69.
