Question

The solubility of in water at a certain temperature is 35.7 g /100. g . Suppose that you have 330.0 g of . What is the minimum volume of water you would need to dissolve it all? (Assume that the density of water is 1.00 g/mL.)

Answer 1

The question is incomplete, here is the complete question:

The solubility of substance X in water at a certain temperature is 35.7 g /100. g. Suppose that you have 330.0 g of substance X. What is the minimum volume of water you would need to dissolve it all? (Assume that the density of water is 1.00 g/mL.)

Answer: The minimum volume of water that would be needed is 940.17 mL

Explanation:

We are given:

Solubility of substance X in water = 35.1 g/100 g

This means that 35.1 grams of substance X is dissolved in 100 grams of water

Applying unitary method:

If 35.1 grams of substance X is dissolved in 100 grams of water

So, 330.0 grams of substance X will be dissolved in = $\frac{100}{35.1}\times 330=940.17g$ of water

To calculate the volume of water, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of water = 1 g/mL

Mass of water = 940.17 g

Putting values in above equation, we get:

$1g/mL=\frac{940.17g}{\text{Volume of water}}\\\\\text{Volume of water}=\frac{940.17g}{1g/mL}=940.17mL$

Hence, the minimum volume of water that would be needed is 940.17 mL