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kramer
3 years ago
10

How many atoms are in 25.00 g of B.

Chemistry
1 answer:
iren2701 [21]3 years ago
6 0

Answer:

\boxed {\boxed {\sf 1.393 *10^{24} \ atoms \ B}}

Explanation:

<u>1. Convert Grams to Moles</u>

Use the molar mass (found on the Periodic Table) to convert from grams to moles.

  • Boron (B): 10.81 g/mol

Use this value as a ratio.

\frac {10.81 \ g \ B }{1 \ mol \ B}

Multiply by the given number of grams.

25.00 \ g \ B *\frac {10.81 \ g \ B }{1 \ mol \ B}

Flip the ratio so the grams of boron cancel out.

25.00 \ g \ B *\frac {1  \ mol \ B }{10.81 \ g \ B}

25.00 *\frac {1  \ mol \ B }{10.81 }

\frac {25.00 \ mol \ B }{10.81 }=2.312673451 \ mol \ B

<u>2. Convert Moles to Atoms</u>

We use Avogadro's Number, 6.02*10²³: the number of particles (atoms, molecules, etc.) in 1 mole of a substance. In this case, the particles are atoms of boron.

\frac {6.02*10^{23} \ atoms \ B} {1 \ mol \ B}

Multiply by the number of moles we calculated.

2.312673451 \ mol \ B *\frac {6.02*10^{23} \ atoms \ B} {1 \ mol \ B}

The moles of boron cancel.

2.312673451  *\frac {6.02*10^{23} \ atoms \ B} {1 }

2.312673451  *6.02*10^{23} \ atoms \ B} =1.39269195*10^{24} \ atoms \ B

The original value of grams has 4 significant figures, so our answer should have the same. For the number we calculated, that is the thousandth place.

1.392\underline69195*10^{24} \ atoms \ B

The 6 tells us to round the 2 to a 3.

1.393 *10^{24} \ atoms \ B

25.00 grams of boron is equal to 1.393*10²⁴ atoms.

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