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kramer
3 years ago
10

How many atoms are in 25.00 g of B.

Chemistry
1 answer:
iren2701 [21]3 years ago
6 0

Answer:

\boxed {\boxed {\sf 1.393 *10^{24} \ atoms \ B}}

Explanation:

<u>1. Convert Grams to Moles</u>

Use the molar mass (found on the Periodic Table) to convert from grams to moles.

  • Boron (B): 10.81 g/mol

Use this value as a ratio.

\frac {10.81 \ g \ B }{1 \ mol \ B}

Multiply by the given number of grams.

25.00 \ g \ B *\frac {10.81 \ g \ B }{1 \ mol \ B}

Flip the ratio so the grams of boron cancel out.

25.00 \ g \ B *\frac {1  \ mol \ B }{10.81 \ g \ B}

25.00 *\frac {1  \ mol \ B }{10.81 }

\frac {25.00 \ mol \ B }{10.81 }=2.312673451 \ mol \ B

<u>2. Convert Moles to Atoms</u>

We use Avogadro's Number, 6.02*10²³: the number of particles (atoms, molecules, etc.) in 1 mole of a substance. In this case, the particles are atoms of boron.

\frac {6.02*10^{23} \ atoms \ B} {1 \ mol \ B}

Multiply by the number of moles we calculated.

2.312673451 \ mol \ B *\frac {6.02*10^{23} \ atoms \ B} {1 \ mol \ B}

The moles of boron cancel.

2.312673451  *\frac {6.02*10^{23} \ atoms \ B} {1 }

2.312673451  *6.02*10^{23} \ atoms \ B} =1.39269195*10^{24} \ atoms \ B

The original value of grams has 4 significant figures, so our answer should have the same. For the number we calculated, that is the thousandth place.

1.392\underline69195*10^{24} \ atoms \ B

The 6 tells us to round the 2 to a 3.

1.393 *10^{24} \ atoms \ B

25.00 grams of boron is equal to 1.393*10²⁴ atoms.

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Balanced chemical equation:

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The balanced equation s given above and it completely follow the law of conservation of mass.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

This law was given by french chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

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