Answer: 8Ω
Explanation:
Since there are two resistors of 4Ω
connected in series, the total resistance (Rtotal) of the circuit is the sum of each resistance.
i.e Rtotal = R1 + R2
R1 = 4Ω
R2 = 4Ω
Rtotal = ?
Rtotal = 4Ω + 4Ω
Rtotal = 8Ω
Thus, the total resistance of the circuit is 8Ω
Answer:
Falso. Se requiere de dos vectores de igual magnitud pero antiparalelos entre sí.
Explanation:
Un vector es un elemento caracterizado por tener magnitud y dirección, sea 
un vector tal que la resultante sea 
(vector nulo). Por Álgebra de los Reales se sabe que todo vector tiene su inverso, es decir, que existe un vector 
tal que:
![(v_{x}, v_{y}) + [-(v_{x},v_{y})] = (0,0)](https://tex.z-dn.net/?f=%28v_%7Bx%7D%2C%20v_%7By%7D%29%20%2B%20%5B-%28v_%7Bx%7D%2Cv_%7By%7D%29%5D%20%3D%20%280%2C0%29)
Esto significa, que el siguiente sistema de ecuaciones debe satisfacerse:
Se requiere de dos vectores de igual magnitud pero antiparalelos entre sí. En consecuencia, la anterior afirmación es falsa.
False, Gamma Rays are the smallest because gamma rays have the shortest wave length
Answer:
r = 0.56 m
Explanation:
The power emitted by the radar is evenly distributed in a sphere, so let's use the ratio of intensity and power
I = P / A
A = P / I
A = 10.0 / 2.50
A = 4 m²
Let's find the radius of the sphere of this area
A = 4π r²
r = √ A / 4π
r = √ 4 / 4π
r = 0.56 m
300 A . s or 300C. The amount of electric charge that flows through an electric bulb that drain a current of 0.25 for 20 minutes is 300 A . s = 300C.
Current is the amount of charge moving through a cross-sectional area of a conductor per second, and the unit for current is the coulomb/second, or ampere. It is define by the equation I = Δq/Δt.
Let's clear Δq from I = Δq/Δt:
20 minutes contains 1200 seconds
Δq = I Δt = (0.25A)(1200s) =
Δq = 300 A . s or 300C.
