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AlexFokin [52]
3 years ago
15

What is total resistor formula

Physics
1 answer:
sp2606 [1]3 years ago
8 0

Answer:

If you know the current and voltage across the whole circuit, you can find total resistance using Ohm's Law: R = V / I.

Explanation:

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Determine the total amount of heat, in joules, required to completely vaporize a 50.0-gram sample of h2o(?) at its boiling point
Tanzania [10]
In order to calculate the amount of energy required, we must first check the latent heat of vaporization of water from literature. The latent heat of vaporization of any substance is the amount of energy required per unit mass to convert that substance from a solid to a liquid. For water this is 2,260 J/g. We now use the formula:
Energy = mass * latent heat
Q = 50 * 2,260
Q = 113,000 J

113,000 Joules of heat energy are required.
3 0
3 years ago
What is the net force needed to lift a full grocery sack weighing 210N uniformly?
Alex
If the sack weighs 210 newtons, then an upward force of 210 newtons
exactly cancels the downward force of gravity, and makes the net vertical
force on the bag zero. 

ANY upward force that's greater than 210 newtons makes the net force
act upward on the bag, and causes it to accelerate upward.
8 0
3 years ago
In the study of Physics, the "Universal Gas Law" is not considered a law at<br> all.true or false
LiRa [457]

Answer: It’s False hope this helps

Explanation:

4 0
3 years ago
An instrument is defective for all of the following conditions EXCEPT:_______
NARA [144]

Answer:

I believe its C

6 0
4 years ago
Water is circulating through a closed system of pipes in a two floor apartment. On the first floor, the water has a gauge pressu
anastassius [24]

Answer:

The value of gauge pressure at outlet = -38557.224 pascal

Explanation:

Apply Bernoulli' s Equation

\frac{P_{1}}{9810} + \frac{V_{1} ^{2}}{19.62} + h_{1} = \frac{P_{2}}{9810} + \frac{V_{2} ^{2}}{19.62} + h_{2} --------------(1)

Where

P_{1} =  Gauge pressure at inlet = 3.70105 pascal

V_{1} = velocity at inlet =  2.4 \frac{m}{sec}

P_{2} = Gauge pressure at outlet = we have to calculate

V_{2} = velocity at outlet = 3.5 \frac{m}{sec}

h_{2} - h_{1} = 3.6 m

Put all the values in equation (1) we get,

⇒ \frac{3.70105}{9810} + \frac{2.4 ^{2}}{19.62} = \frac{P_{2}}{9810} + \frac{3.5 ^{2}}{19.62} + 3.6

⇒ 0.294 = \frac{P_{2}}{9810} + 0.6244 + 3.6

⇒ \frac{P_{2}}{9810} = 0.294 - 0.6244 - 3.6

⇒ \frac{P_{2}}{9810} = - 3.9304

⇒ P_{2} = - 38557.224 pascal

This is the value of gauge pressure at outlet.

3 0
3 years ago
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