To solve this problem we will derive the expression of the precession period from the moment of inertia of the given object. We will convert the units that are not in SI, and finally we will find the precession period with the variables found. Let's start defining the moment of inertia.

Here,
M = Mass
R = Radius of the hoop
The precession frequency is given as

Here,
M = Mass
g= Acceleration due to gravity
d = Distance of center of mass from pivot
I = Moment of inertia
= Angular velocity
Replacing the value for moment of inertia


The value for our angular velocity is not in SI, then


Replacing our values we have that


The precession frequency is




Therefore the precession period is 5.4s
Potential Energy= 24m * 14kg * 9.8N/kg = 3292.8J
Explanation:
Below is an attachment containing the solution.
Acceleration due to gravity
The cube has 6 equal, square, foil faces. The mass of foil for each face is (380/6) milligrams.
The surface area of each piece is (380)/(6•11) cm^2.
The length of each side of the piece is √(380/6•11) cm
That's about 2.4 cm .
It's a cute little foil cube, just under 1-inch each way.