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natulia [17]
3 years ago
8

If the average gauge pressure in the vein is 12200 Pa, what must be the minimum height of the bag in order to infuse glucose int

o the vein? Assume that the specific gravity of the solution is 1.02. The acceleration of gravity is 9.8 m/s 2 . Answer in units of m
Physics
1 answer:
Amanda [17]3 years ago
6 0

Answer:

h = 1.22 m

Explanation:

Given:

Pressure in the vein = 12200 Pa

Specific gravity of the liquid  = 1.02

now,

the pressure due to a fluid is given as:

P = pgh

where,

P is the pressure,

ρ is the density of fluid = specific gravity x density of water = 1.02 x 1000 kg/m³

ρ = 1020 kg/m³

g is the acceleration due to the gravity = 9.81m/s²

h is the height

thus,

h = P/pg =\frac{12200}{1020\times 9.8}=1.22 m

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vovikov84 [41]

Answer:

The train's displacement is zero.

Explanation:

Given data,

The time taken by the train from NY to Washington and back is, t = 6 h 5 min

The distance between the two stations is, d = 363 km

Therefore, the total distance the train traveled is, d' = 726 km

The displacement is defined as the change in position coordinates with respect to its original position.

If the train travels from one point and returns back to the same point after some time, there is no change in the position coordinates with respect to its original position.

Hence, the train's displacement is zero.

3 0
4 years ago
If we start with 1.000 g of cobalt-60, 0.675 g will remain after 3.00 yr. this means that the of is _____
Tju [1.3M]
<span>Cobalt-60 is undergoing a radioactivity decay.

The formula of the decay is n=N(1/2)</span>∧(T/t).
<span>Where N </span>⇒ original mass of cobalt
<span>           n </span>⇒ remaining mass of cobalt after 3 years
          T ⇒ decaying period
           t ⇒ half-life of cobalt.

So,
0.675 = 1 × 0.5∧(3/t)
log 0.675 = log 0.5∧(3/t)
3/t = log 0.675 ÷log 0.5
 3/t= 0.567

t = 3÷0.567
  = 5.290626524

the half-life of Cobalt-60 is 5.29 years. 

<span>           
</span><span>
</span>
8 0
3 years ago
A frog jumps for 4.0 seconds at a maximum horizontal distance of 0.8m. what is its velocity along the road?
Lerok [7]

Answer:

The frog's horizontal velocity is 0.2 m/s.

Explanation:

To solve this problem, we must first remember what velocity is and how we solve for it.  Velocity can be solved for using the formula x/t, where x represents horizontal distance and t represents time (in seconds), that it takes to travel this distance.  If we plug in the given numbers for these variables and solve, we get the following:

v = x/t

v = 0.8m/4s

v = 0.2 m/s

Therefore, the correct answer is 0.2 m/s.  We can verify that these units are correct because the formula calls for distance divided by time, so meters per second is a sensible answer.

Hope this helps!

3 0
3 years ago
Which lists three organic biological molecules?
igor_vitrenko [27]

Answer:

B

Explanation:

I'm learning it in science.

8 0
3 years ago
You are on a rollercoaster going around a curve. Your speed is a constant 40 miles per hour. Are you accelerating?
vodomira [7]
No, you are at a constant rate which means that you are always at 40mph
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