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mezya [45]
2 years ago
10

Aiden has basketball practice after school on Mondays, Wednesdays, and Fridays. He has practiced really hard this year to get be

tter and his coach has commented that he appreciates his commitment and hard work this year. This weekend, his family is going to visit his grandma because it is her 80th birthday. Grandma lives four hours away, though, so his mom tells him that they are going to leave right after school on Friday so they can get there before it gets too late. Aiden is upset because he is going to miss practice, but he knows it is important to visit his grandma. what type of responsibility conflict is this?
Physics
1 answer:
Jlenok [28]2 years ago
6 0
Ok I’ll help you I think 20 -192 = 1928172 then ur divided • by 181$1 then u get 244141551611671718181919191827337533535352526
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Un movil de masa 12Kg sobre el cual estan actuando varias fuerzas F_1=48N, F_2=60N y F_3=30N Calcular la aceleracion con la cual
Nikitich [7]

Answer:

Lamentablemente el problema está incompleto, pues no sabemos la dirección en la que se aplican las fuerzas. Por ello, voy a resolver el problema asumiendo dos casos. (abajo se puede ver una imagen donde se describe cada caso)

1) Todas las fuerzas están en la misma dirección.

Entonces la fuerza neta será la suma de las 3 fuerzas, entonces:

F = 48N + 60N + 30N = 138N

Y por la segunda ley de Newton sabemos que:

F = m*a

fuerza igual a masa por aceleración.

Entonces la aceleración está dada por:

a = F/m = 138N/12kg = 11.5 m/s^2

2) Segundo caso, suponemos que F1 es opuesta a F2 y F3

En este caso, la fuerza neta será:

F = F2 + F3 - F1 = 60N + 30N - 48N = 42N

En este caso, la aceleración será:

a = 42N/12kg = 3.5 m/s^2

7 0
2 years ago
Can someone help me?​
Leviafan [203]

Car X traveled 3d distance in t time.  Car Y traveled 2d distance in t time. Therefore, the speed of car X, is 3d/t,  the speed of car Y, is 2d/t. Since speed is the distance taken in a given time.

In figure-2, they are at the same place, we are asked to find car Y's position when car X is at line-A. We can calculate the time car X needs to travel to there. Let's say that car X reaches line-A in t' time.

V_x .t' = 3d\\ \frac{3d}{t} .t' = 3d\\ t'=t

Okay, it takes t time for car X to reach line-A. Let's see how far does car Y goes.

V_y.t = \frac{2d}{t} .t = 2d

We found that car Y travels 2d distance. So, when car X reaches line-A, car Y is just a d distance behind car X.

4 0
2 years ago
You and your friend are pushing a box at the same constant speed. You pushed 20 feet in 10 minutes, your friend was pushing for
anzhelika [568]

Answer:

60 N.C

Explanation:

The box will move in the direction of the push and pull with a force of 60 N. C.

7 0
2 years ago
Below is a single strand of DNA, what is the complementary base pair for the strand?
GREYUIT [131]
The complementary base pair is:
TTC, CTG, AGT, CTA.
5 0
2 years ago
A 50-cm-long spring is suspended from the ceiling. A 270 g mass is connected to the end and held at rest with the spring unstret
I am Lyosha [343]

Answer:

The spring constant is 45.94 N/m.

Explanation:

Given that,

Length = 50 cm

Mass = 270 g

Stretching the spring = 24 cm

We need to calculate the spring constant

Using formula of energy

The change in potential energy equal to the change in kinetic energy.

mgh=\dfrac{1}{2}kx^2

Put the value into the formula

270\times10^{-3}\times9.8\times50\times10^{-2}=\dfrac{1}{2}\times k\times(24\times10^{-2})^2

k=\dfrac{2\times270\times10^{-3}\times9.8\times50\times10^{-2}}{(24\times10^{-2})^2}

k=45.94\ N/m

Hence, The spring constant is 45.94 N/m.

3 0
3 years ago
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