It is more difficult over easy. Since you haven't figured it out and came here to ask.
Answer:
+1
Explanation:
Na₂O₂
NOTE: the oxidation number of oxygen is always –2 except in peroxides where it is –1.
Thus, we can obtain the oxidation number of sodium (Na) in Na₂O₂ as illustrated below:
Na₂O₂ = 0 (oxidation number of ground state compound is zero)
2Na + 2O = 0
O = –1
2Na + 2(–1) = 0
2Na – 2 = 0
Collect like terms
2Na = 0 + 2
2Na = 2
Divide both side by 2
Na = 2/2
Na = +1
Thus, the oxidation number of sodium (Na) in Na₂O₂ is +1
Answer:
Hexanoic acid is water insoluble and sodium hexanoate is water soluble
Explanation:
Hexanoic acid is water insoluble because of presence of long 6 membered non polar and hydrophobic hydrocarbon chain.
When hexanoic acid is treated with NaOH, it is converted to an ionic salt sodium hexanoate which is highly soluble in water because of it's ionic nature.
So, the reaction is given as:
Hexanoic acid + NaOH Sodium hexanoate + water
Reaction in terms of molecular structure has been shown below.
Answer:
(f - g)(2) = -6
Step-by-step explanation:
(f - g)(2) = (-2x + 8) - 5x, where x=2
= (-2(2) + 8) - 5(2)
= (-4 + 8) - 10
= 4 - 10
= -6
(f - g)(2) = -6
Answer:
The solubility of KNO₃ at 40° C is 1 mol/dm³
Explanation:
The solubility of a substance is the number of moles of that substance (solute) contained in a unit volume of solvent at that particular temperature.
Now, Solubility = n/V where n = number of moles of KNO₃ and V = volume of saturated solution = 50.0 cm³ = 0.05 dm³
n = m/M where m = mass of KNO₃ = 5.05 g and M = molar mass of KNO₃ = 101 g/mol
n = 5.05 g/101 g/mol = 0.05 mol
Solubility = n/V
= 0.05 mol/0.05 dm³
= 1 mol/dm³
So, the solubility of KNO₃ at 40° C is 1 mol/dm³