All categories

3 years ago

HELLPP!!!

Chemistry

2 answers:

azamat3 years ago

6 0

Answer: i gotcu the answer is mass

Explanation: The more weight of the object the more its subject to gravity like a feather barley is while a bowling ball smashes into the ground :D

Karo-lina-s [1.5K]3 years ago

6 0

The answer is mass.

You might be interested in

A sample of neon gas occupies a volume of 752ml at 25k. What volume will the gas occupy at 80k if the pressure remains constant

Anettt [7]

Answer:

The gas occupy 2406.4 mL at 80 K.

Explanation:

Given data:

Initial volume of gas = 752 mL

Initial temperature = 25 K

Final temperature = 80 K

Final volume = ?

Solution:

The given problem is solved by using charle's law.

V₁/T₁ = V₂/T₂

V₂ = V₁. T₂ /T₁

V₂ = 752 mL × 80 k / 25 K

V₂ = 60160 mL. k/25 K

V₂ = 2406.4 mL

7 0

2 years ago

What are two versions of genes called and how are they diffrent?

Stolb23 [73]

Answer with Explanation:

Different versions of a gene are called alleles. Alleles are described as either dominant or recessive depending on their associated traits. Since human cells carry two copies of each chromosome they have two versions of each gene.

8 0

2 years ago

Even though the molecular formula of acetylene is C2H2, and that of benzene is C6H6, these compounds have the same percent compo

alexandr402 [8]

Answer:

Explanation:

The empirical formular is the simplest formular of a compound. It shows the relative number of elements present in a compounds. It shows the number of atoms of elements present in simple ratios.

In both compounds, the ratio of the carbon to hydrogen s 1:1

In C2H2;

C : H = 2 : 2 (Which is equivalent to 1 : 1)

In C6H6;

C : H = 6 : 6 (Which is equivalent to 1 : 1)

This means the empirical formular is CH

7 0

3 years ago

Which reaction below represents the first ionization of sb?which reaction below represents the first ionization of ?sb2−(g) → sb

zubka84 [21]

Answer is: Sb(g) → Sb⁺(g) + e⁻.
Neutral atom in gas state lose one valence electron and become cation with postive charge.
<span>The first ionisation energy is the energy required to remove one mole of the valence electrons from one mole of gaseous atoms to produce one mole of gaseous ions each with a charge of 1+.</span>
<span>Most metals have strong metallic bond, because strong electrostatic attractive force between valence electrons (metals usually have low ionization energy and lose electrons easy) and positively charged metal ions.

</span>

6 0

3 years ago

Read 2 more answers

48.0 mL of 1.70 M CuCl2(aq) and 57.0 mL of 0.800 M (NH4)2S(aq) are mixed together to give CuS(s) as a precipitate. The other pro

artcher [175]

Answer:

The concentration of the Cu(II) ion is 0.777M

Explanation:

Step 1: Data given

Volume of 1.70 M CuCl2 = 48.0 mL = 0.0480 L

Volume of 0.800 M (NH4)2S = 57.0 mL = 0.0570 L

Step 2: The balanced equation

CuCl2 (aq) + (NH4)2S (aq) → 2 NH4Cl (aq) + CuS (s)

Step 3: Calculate moles CuCl2

moles CuCl2 = 0.0480 L * 1.70 M=0.0816 moles

Step 4: Calculate moles (NH4)2S

moles (NH4)2S = 0.0570 L * 0.800 M = 0.0456 moles

Step 5: Calculate the limiting reactant

The ratio between CuCl2 and (NH4)2S is 1 : 1 so (NH4)2S is the limiting reactant . IT will completely be consumed (0.0456 moles).

CuCl2 is in excess. There will remain 0.0816 - 0.0456 = 0.0360 moles

Step 6: Calculate moles of CuS

For 1 mol CuCl2 we need 1 mol (NH4)2S to produce 2 moles of NH4Cl and 1 mol CuS

For 0.0456 moles we'll produce 0.0456 moles CuS

Step 7: Calculate moles of Cu(II)ion

There remains 0.0360 moles CuCl2.

There will be 0.0456 moles CuS produced

Total moles Cu^2+ = 0.0816 moles

Step 8: Calculate concentration of Cu(II) ion

Concentration = moles / volume

Concentration = 0.0816 moles / (0.048+0.057)

Concentration = 0.777 M

The concentration of the Cu(II) ion is 0.777M

7 0

3 years ago