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tatiyna
4 years ago
5

Match the facts to the examples. The force of gravity increases with an increase in the mass of objects. Acceleration due to gra

vity is independent of the mass of objects. Air resistance increases with an increase in the surface area of objects. Two falling inflated balls of different masses land at the same time. arrowRight A large, massive dog weighs more than a small dog. arrowRight A crumpled ball of paper falls faster than a sheet of paper of the same mass. arrowRight
Physics
2 answers:
sergeinik [125]4 years ago
8 0

The force of gravity increases with an increase in the mass of objects. . . . A large, massive dog weighs more than a small dog.

Acceleration due to gravity is independent of the mass of objects. . . . Two falling inflated balls of different masses land at the same time.

Air resistance increases with an increase in the surface area of objects. . . . A crumpled ball of paper falls faster than a sheet of paper of the same mass.

arrowRight . . . . a button on a computer keyboard that causes the cursor to move to the right on the screen when pushed

arrowRight . . . . a button on a computer keyboard that causes the cursor to move to the right on the screen when pushed  

arrowRight . . . . a button on a computer keyboard that causes the cursor to move to the right on the screen when pushed

never [62]4 years ago
5 0

Answer:

1). The force of gravity increases with an increase in the mass of objects

    A large, massive dog weighs more than a small dog.

2). Acceleration due to gravity is independent of the mass of objects

    Two falling inflated balls of different masses land at the same time.

3). Air resistance increases with an increase in the surface area of objects

    A crumpled ball of paper falls faster than a sheet of paper of the same mass.

Explanation:

1). Force of gravity on an object placed near the surface of earth is given by

F = mg

so here if mass of the object is more then it will have more gravitational force due to earth so massive dog weigh more than small dog

2). Acceleration due to gravity is acceleration of an object due to its gravitational force

a = \frac{F}{m} = g

so here for all objects near the surface of earth acceleration is due to gravity and remains constant.

So here if two different object will fall from same height under gravity then both will reach ground at same time.

3). Air drag or air resistance depends on area of object so if area of object is more then it will experience more air drag

This will show that if a paper is crumpled then its area will be less and then it will have less resistance while open paper has more area and due to its more resistance it will fall slowly than crumpled paper

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consider two stars, star a and star b. star a has a temperature of 4900 k , and star b has a temperature of 9900 k . how many ti
ValentinkaMS [17]

The Energy flux from Star B is 16 times of the energy flux from Star A.

We have Two stars - A and B with 4900 k and 9900 k surface temperatures.

We have to determine how many times larger is the energy flux from Star B compared to the energy flux from Star A.

<h3>State Stephen's Law?</h3>

Stephens law states that if E is the energy radiated away from the star in the form of electromagnetic radiation, T is the surface temperature of the star, and σ is a constant known as the Stephan-Boltzmann constant then-

$\frac{Energy}{Area} = \sigma\times T^{4}

Now -

Energy emitted per unit surface area of Star is called Energy flux. Let us denote it by E. Then -

$E= \sigma\times T^{4}

Now -

For Star A →

T_{A} = 4900 K

For Star B →

T_{B} = 9900 K

Therefore -

$\frac{T_{B} }{T_{A} } =\frac{9900}{4900}

\frac{T_{B} }{T_{A} }= 2.02 = 2 (Approx.)

Now -

Assume that the energy flux of Star A is E(A) and that of Star B is E(B). Then -

$\frac{E(B)}{E(A)} = \frac{\sigma\times T(B)^{4} }{\sigma \times T(A)^{2} }

E(B) = E(A) x (\frac{T(B)}{T(A)} )^{4}

E(B) = E(A) x 2^{4}

E(B) = 16 E(A)

Hence, the Energy flux from Star B is 16 times of the energy flux from Star A.

To learn more about Stars, visit the link below-

brainly.com/question/13451162

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4 0
2 years ago
In a mattress test, you drop a 7.0 kg bowling ball from a height of 1.5 m above a mattress, which as a result compresses 15 cm a
Assoli18 [71]

Answer:

(c) 10.29 J

(d) 113.19 J

(e) 113.19 J

(f) 10061 N/m

Explanation:

15 cm = 0.15 m

Let g = 9.8 m/s2

(c) The work done by gravitational force is the product of gravity force and the distance compressed

E_p = mgx = 7*9.8*0.15 = 10.29 J

(d) By using law of energy conservation with potential energy reference being 0 at the maximum compression point. As the ball falls and come to a stop at the compression point, its potential energy is transferred to elastic energy, which is the work that the mattress does on the ball:

E_p = E_e

E_e = mgh

where h = 1.5 + 0.15 = 1.65 m is the vertical distance that it falls.

E_e = 7*9.8*1.65 = 113.19 J

(e) Before the compression, the potential energy of the mattress is 0. After the compression, the potential energy is 113.19J. So it has increased by 113.19J due to the potential energy transferred from the falling ball.

(f) E_e = 113.19 = kx^2/2

k0.15^2/2 = 113.19

k = 10061 N/m

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