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tatiyna
3 years ago
5

Match the facts to the examples. The force of gravity increases with an increase in the mass of objects. Acceleration due to gra

vity is independent of the mass of objects. Air resistance increases with an increase in the surface area of objects. Two falling inflated balls of different masses land at the same time. arrowRight A large, massive dog weighs more than a small dog. arrowRight A crumpled ball of paper falls faster than a sheet of paper of the same mass. arrowRight
Physics
2 answers:
sergeinik [125]3 years ago
8 0

The force of gravity increases with an increase in the mass of objects. . . . A large, massive dog weighs more than a small dog.

Acceleration due to gravity is independent of the mass of objects. . . . Two falling inflated balls of different masses land at the same time.

Air resistance increases with an increase in the surface area of objects. . . . A crumpled ball of paper falls faster than a sheet of paper of the same mass.

arrowRight . . . . a button on a computer keyboard that causes the cursor to move to the right on the screen when pushed

arrowRight . . . . a button on a computer keyboard that causes the cursor to move to the right on the screen when pushed  

arrowRight . . . . a button on a computer keyboard that causes the cursor to move to the right on the screen when pushed

never [62]3 years ago
5 0

Answer:

1). The force of gravity increases with an increase in the mass of objects

    A large, massive dog weighs more than a small dog.

2). Acceleration due to gravity is independent of the mass of objects

    Two falling inflated balls of different masses land at the same time.

3). Air resistance increases with an increase in the surface area of objects

    A crumpled ball of paper falls faster than a sheet of paper of the same mass.

Explanation:

1). Force of gravity on an object placed near the surface of earth is given by

F = mg

so here if mass of the object is more then it will have more gravitational force due to earth so massive dog weigh more than small dog

2). Acceleration due to gravity is acceleration of an object due to its gravitational force

a = \frac{F}{m} = g

so here for all objects near the surface of earth acceleration is due to gravity and remains constant.

So here if two different object will fall from same height under gravity then both will reach ground at same time.

3). Air drag or air resistance depends on area of object so if area of object is more then it will experience more air drag

This will show that if a paper is crumpled then its area will be less and then it will have less resistance while open paper has more area and due to its more resistance it will fall slowly than crumpled paper

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Can you please tell me what this is
Anna [14]

Answer:

200000 J

Explanation:

From the question given above, the following data were obtained:

Mass (m) of roller coaster = 1000 Kg

Velocity (v) of roller coaster = 20 m/s

Kinetic energy (KE) =?

Kinetic energy is simply defined as the energy possess by an object in motion. Mathematically, it can be expressed as:

KE = ½mv²

Where

KE => is the kinetic energy.

m =>is the mass of the object

V => it the velocity of the object.

With the above formula, we can obtain the kinetic energy of the roller coaster as follow:

Mass (m) of roller coaster = 1000 Kg

Velocity (v) of roller coaster = 20 m/s

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 1000 × 20²

KE = 500 × 400

KE = 200000 J

Therefore, the kinetic energy of the roller coaster is 200000 J.

4 0
2 years ago
You push a box with a force of 80 n. if the net force on the box is 50 n, what is the force on the box due to sliding friction?
Elodia [21]

The force of the sliding friction is 30 N.

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2 years ago
Light incident on a glass sheet is partly reflected and partly refracted. How is the reflected ray different from the refracted
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Answer:

E. The refracted ray is vertically polarized whereas the reflected ray is horizontally polarized.

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3 years ago
A block weighting 400kg rests on a horizontal surface and support on top of it another block of weight 100kg placed on the top o
masha68 [24]

The horizontal force applied to the block is approximately 1,420.84 N

The known parameters;

The mass of the block, w₁ = 400 kg

The orientation of the surface on which the block rest, w₁ = Horizontal

The mass of the block placed on top of the 400 kg block, w₂ = 100 kg

The length of the string to which the block w₂ is attached, l = 6 m

The coefficient of friction between the surface, μ = 0.25

The state of the system of blocks and applied force = Equilibrium

Strategy;

Calculate the forces acting on the blocks and string

The weight of the block, W₁ = 400 kg × 9.81 m/s² = 3,924 N

The weight of the block, W₂ = 100 kg × 9.81 m/s² = 981 N

Let <em>T</em> represent the tension in the string

The upward force from the string = T × sin(θ)

sin(θ) = √(6² - 5²)/6

Therefore;

The upward force from the string = T×√(6² - 5²)/6

The frictional force = (W₂ - The upward force from the string) × μ

The frictional force, F_{f2} = (981 - T×√(6² - 5²)/6) × 0.25

The tension in the string, T = F_{f2} × cos(θ)

∴ T = (981 - T×√(6² - 5²)/6) × 0.25 × 5/6

Solving, we get;

T = \dfrac{5886}{\sqrt{6^2 - 5^2} + 28.8} \approx 183.27

Frictional \ force, F_{f2} = \left (981 -  \dfrac{5886}{\sqrt{6^2 - 5^2} + 28.8}  \times \dfrac{\sqrt{6^2 - 5^2} }{6} \times  0.25 \right) \approx 219.92

The frictional force on the block W₂, F_{f2} ≈ 219.92 N

Therefore;

The force acting the block w₁, due to w₂ F_{w2} = 219.92/0.25 ≈ 879.68

The total normal force acting on the ground, N = W₁ + \mathbf{F_{w2}}

The frictional force from the ground, \mathbf{F_{f1}} = N×μ + \mathbf{F_{f2}} = P

Where;

P = The horizontal force applied to the block

P = (W₁ + \mathbf{F_{w2}}) × μ + \mathbf{F_{f2}}

Therefore;

P = (3,924 + 879.68) × 0.25 + 219.92 ≈ 1,420.84

The horizontal force applied to the block, P ≈ 1,420.84 N

Learn more about friction force here;

brainly.com/question/18038995

3 0
2 years ago
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