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Nonamiya [84]
4 years ago
8

How do you determine half life

Physics
1 answer:
kenny6666 [7]4 years ago
4 0

Answer:

T= In(2)/___ =__ In(2)

Explanation:

the equation pices arnt on the keyboard so i put the blanks

sorry

jope it helps some. Have a good day ir night! :)

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Has a definite shape and definite volume. Question 4 options: liquid gas solid
ad-work [718]

Answer:

solid

Explanation:

solid

3 0
3 years ago
Excited hydrogen atoms radiate energy in the _________
sveticcg [70]

Answer:

infrared, visible and ultraviolet regions.

Explanation:

7 0
3 years ago
In the Bohr’s model of the hydrogen atom, the electron moves in a circular orbit of radius 5.041 × 10−11 m around the proton. As
Ilia_Sergeevich [38]

Answer:

The orbital speed of the electron is 2.296 x 10⁶ m/s

Explanation:

Given;

radius of the circular orbit, r = 5.041 × 10⁻¹¹ m

In the Bohr’s model of the hydrogen atom, the velocity of the electron is given as;

V = \frac{nh}{2\pi mr}

where;

h is Planck's constant

m is mass of electron

r is the radius of the circular orbit

n is the energy level of hydrogen in ground state

Substitute in these values and solve for V

V = \frac{nh}{2\pi mr} = \frac{1*6.626*10^{-34}}{2\pi *9.11 *10^{-31}*5.041*10^{-11}}\\\\V = 2.296*10^6  \ m/s

Therefore, the orbital speed of the electron is 2.296 x 10⁶ m/s

4 0
4 years ago
A city planner is working on the redesign of a hilly portion of a city. An important consideration is how steep the roads can be
Artyom0805 [142]

Explanation:

It is known that relation between force and acceleration is as follows.

                      F = m \times a

I is given that, mass is 1090 kg and acceleration is 21 m/s. Therefore, we will calculate force as follows.

              F = m \times a      

                 = 1090 \times (\frac{21}{16})

                 = 1430.625 N

Also, it is known that

      sin(\theta) = \frac{\text{Force car can exert}}{\text{Force gravity pulls car}}

      sin(\theta) = \frac{1430.625 N}{(1090 \times 9.8) N}

        \theta = 7.70 degrees

Thus, we can conclude that the maximum steepness for the car to still be able to accelerate is 7.70 degrees.

8 0
3 years ago
The area in which the attraction and the repulsion of a magnet's poles are felt is a(n)
docker41 [41]

The are is called a magnetic field.


8 0
4 years ago
Read 2 more answers
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