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frosja888 [35]
3 years ago
6

I NEED HELP PLEASE Coment if u singal

Mathematics
2 answers:
ICE Princess25 [194]3 years ago
4 0

Answer:

x> -10

Step-by-step explanation:

in order to find what the value of X is you have to multiply the 5 of the denominator into the -6 which would make -30.

You would then divide by 3 in order to get x by itself and would get -30÷3= -10

therefore the answer should be greater than -10

Hope this helped :)

Fofino [41]3 years ago
3 0

Answer:

x > -10

Step-by-step explanation:

\frac{3x}{5} > -6

Multiply both sides by 5/3

\frac{5}{3} * \frac{3x}{5} > \frac{5}{3} *(-6)

Reduce Everything

x  > -5*2

Multiply

x > -10

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there are 6 times as many ways to arrange the letters in the word "sleeplessness" as there are to arrange the letters in the wor
EastWind [94]

Using arrangements of words, it is found that the statement is true.

------------------

  • Suppose a word has n letters.
  • Considering that m of these letters are repeating, each n_1,n_2,...,n_m times.
  • The number of distinct ways the word can be arranged is given by:

N = \frac{n!}{n_1\times n_2 \times ... n_m}

------------------

  • The word "sleeplessness" has 13 letters.
  • s repeats 5 times.
  • e repeats 4 times.
  • l repeats 2 times.

Thus, the number of ways to arrange the letters is given by:

N_1 = \frac{13!}{5!4!2!}

------------------

  • The word "senselessness" has 13 letters.
  • s repeats 6 times.
  • e repeats 4 times.
  • n repeats 2 times.

Thus, the number of ways to arrange the letters is given by:

N_2 = \frac{13!}{6!4!2!}

------------------

Finding the ratio of N_2 to N_1:

\frac{N_2}{N_1} = \frac{\frac{13!}{5!4!2!}}{\frac{13!}{6!4!2!}} = \frac{13!}{5!4!2!} \times \frac{6!4!2!}{13!} = \frac{6!}{5!} = 6

Thus, since the ratio is 6, the statement is true.

A similar problem is given at brainly.com/question/16790460

8 0
3 years ago
Read 2 more answers
12) Find the sum, S7, for the geometric series (1 + 5 + 25+ --- + 15625).
vfiekz [6]

Answer:

Find the (r) between adjacent members

a2/a1=+25/5=5

a3/a2=+125/+25=5

a4/a3=+625/+125=5

a5/a4=+3125/+625=5

a6/a5=+15625/+3125=5

The ration (r) between every two adjacent members of the series is constant and equal to 5

General Form: a

n

=a

1

×r

n-1

This geometric series: a

n

=5×5

n-1

The nature of this series

Sum of finite geometric series members

sum of a geometric series

The sum of our particular series

a 1-rn = 5 1-56 = 5 1-15625 = 5 -15624 =5×3906=19530

1-r 1-5 -4 -4

Finding the n

th

element

a2 =a1×r2-1  =a1×r1 =5×51 =25

a3 =a1×r3-1  =a1×r2 =5×52 =125

a4 =a1×r4-1  =a1×r3 =5×53 =625

a5 =a1×r5-1  =a1×r4 =5×54 =3125

a6 =a1×r6-1  =a1×r5 =5×55 =15625

a7 =a1×r7-1  =a1×r6 =5×56 =78125

a8 =a1×r8-1  =a1×r7 =5×57 =390625

a9 =a1×r9-1  =a1×r8 =5×58 =1953125

a10 =a1×r10-1  =a1×r9 =5×59 =9765625

a11 =a1×r11-1  =a1×r10 =5×510 =48828125

a12 =a1×r12-1  =a1×r11 =5×511 =244140625

a13 =a1×r13-1  =a1×r12 =5×512 =1220703125

a14 =a1×r14-1  =a1×r13 =5×513 =6103515625

a15 =a1×r15-1  =a1×r14 =5×514 =30517578125

a16 =a1×r16-1  =a1×r15 =5×515 =152587890625

8 0
3 years ago
How do you find the area of a irregular shape
antoniya [11.8K]
You need to split up the irregular shape into shapes that you are familiar with them find the area of each piece and add it together. i’m not sure if that made sense.
6 0
3 years ago
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Use expressions for odd integers to confirm the conjecture that the product for two odd integers is an odd integer.
Mandarinka [93]

k, n - integers  

2k+1  - an odd integer

2n+1  - another odd integer

The product of them:

  (2k + 1)(2n + 1) =

= 4kn + 2k + 2n + 1 =

= 2(2kn + k + n) + 1

The product of integers (2kn) is integer

and the sum of them (2kn+k+n) also is integer

So  (2k + 1)(2n + 1)  = 2(2kn + k + n) + 1  is an odd integer

4 0
4 years ago
Find the measure of x. Line PU has points R and S between points P and U, lines QR and ST are parallel, line QR intersects line
Genrish500 [490]

The value of x is 1.

* Let's explain how to solve the problem

- Line PU has points R and S between points P and U

- Line QR intersects line PU at point R

- Line ST intersects line PU at point S

- Lines QR and ST are parallel

- Look to the attached figure

∵ QR // ST

∴ m∠TSU = m∠QRU ⇒ corresponding angles

∵ m∠TSU = 15(x + 2)°

∴ m∠QRU = 15(x + 2)

∵ Points P, R, S lie on the same line

∵ RQ intersects PS at R

∵ m∠PRQ + m∠QRU = 180° ⇒ straight angle

∵ m∠PRQ = 135°

∵ m∠QRU = 15(x + 2)°

∴ 135 + 15(x + 2) = 180

∴ 135 + 15x + 30 = 180

- Add like terms

∴ 15x + 165 = 180

- Subtract 165 from both sides

∴ 15x = 15

- Divide both sides by 15

∴ x = 1

∴ The value of x is 1

In geometry, parallel lines are coplanar instantly traces that do not intersect at any factor. Parallel planes are planes in identical three-dimensional space that in no way meet. Parallel curves are curves that do not touch every different or intersect and hold a set minimal distance

In mathematics, the intersection of or more gadgets is any other item that includes the whole thing that is contained in all the items simultaneously.

Learn more about parallel lines here : brainly.com/question/24756209

#SPJ4

4 0
2 years ago
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