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Andrews [41]
3 years ago
13

5L=__ML Express your answer in scientific notation 5 x 109 5x 106 5x 103

Physics
2 answers:
Sphinxa [80]3 years ago
7 0

Answer:

5000ml is the answer

Explanation:

multiply 5 time 1000

stiks02 [169]3 years ago
6 0
5000 is the answer to this
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Hi! Can you help me? :) A satellite's speed is 10,000 m/s. After 1 min, it is 5,000 m/s. What is the satellite's acceleration? T
Kruka [31]
<span>a = ΔV/Δt = (5000-10000)/60 = -500/6 = -83.(3) m/sec^2</span>
7 0
3 years ago
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A hiker walks 200 m west and then walks 100 m north. In what direction is her resulting displacement?a. northb. westc. northwest
emmainna [20.7K]

Answer:

Option (C) is correct.

Explanation:

Assuming that the hiker starts walking from the origin O as shown in the figure.

First, he walks 200 m west to point A (say), then he walks 100 m north to the final point B (say) as shown in the figure.

The final point B is in the north-west direction, therefore, the resulting point is in the north-west direction.

Hence, option (C) is correct.

7 0
3 years ago
You exert a 100-N force on a pulley system to lift 300-N. What is the mechanical advantage of this system? How many sections of
Andrei [34K]

Answer:

Mechanical advantage = 3

Explanation:

You exert a 100-N force on a pulley system to lift 300-N.

The mechanical advantage of the system is given by the ratio of output force to the input force.

Here, output force = 300 N and input force = 100 N

Mechanical advantage,

m=\dfrac{300}{100}\\\\m=3

Mechanical advantage is 3 it means that there are 3 sections of rope support. Hence, this is the required solution.

8 0
3 years ago
The earth and the moon exert forces on each other which forces is greater? explain
Helen [10]

Thank you for your question, what you say is true, the gravitational force exerted by the Earth on the Moon has to be equal to the centripetal force.

An interesting application of this principle is that it allows you to determine a relation between the period of an orbit and its size. Let us assume for simplicity the Moon's orbit as circular (it is not, but this is a good approximation for our purposes).

The gravitational acceleration that the Moon experience due to the gravitational attraction from the Earth is given by:

ag=G(MEarth+MMoon)/r2

Where G is the gravitational constant, M stands for mass, and r is the radius of the orbit. The centripetal acceleration is given by:

acentr=(4 pi2 r)/T2

Where T is the period. Since the two accelerations have to be equal, we obtain:

(4 pi2 r) /T2=G(MEarth+MMoon)/r2

Which implies:

r3/T2=G(MEarth+MMoon)/4 pi2=const.

This is the so-called third Kepler law, that states that the cube of the radius of the orbit is proportional to the square of the period.

This has interesting applications. In the Solar System, for example, if you know the period and the radius of one planet orbit, by knowing another planet's period you can determine its orbit radius. I hope that this answers your question.


8 0
3 years ago
A mechanic needs to replace the motor for a merry-go-round. The merry-go-round should accelerate from rest to 1.5 rad/s in 6.0s
pashok25 [27]

Answer:

109656.25 Nm

Explanation:

\omega_f = Final angular velocity = 1.5 rad/s

\omega_i = Initial angular velocity = 0

\alpha = Angular acceleration

t = Time taken = 6 s

m = Mass of disk = 29000 kg

r = Radius = 5.5 m

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\dfrac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\dfrac{1.5-0}{6}\\\Rightarrow \alpha=0.25\ rad/s^2

Torque is given by

\tau=I\alpha\\\Rightarrow \tau=\dfrac{1}{2}mr^2\alpha\\\Rightarrow \tau=\dfrac{1}{2}29000\times 5.5^2\times 0.25\\\Rightarrow \tau=109656.25\ Nm

The torque specifications must be 109656.25 Nm

5 0
3 years ago
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