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Julli [10]
3 years ago
5

using the following data for july, calculate the cost of goods manufactured: beginning finished goods inventory 150,475. Ending

finished goods inventory 145,750. sales 400,000. Gross Margin 120,000. The cost of goods manufactured was
Engineering
1 answer:
Alla [95]3 years ago
5 0

Answer:

The correct response is "$275,275".

Explanation:

The given values are:

Sales,

= 400,000

Gross margin,

= 120,000

Beginning Inventory goods,

= 150,475

Finished inventory goods,

= 145,750

Now,

The cost of goods sold will be:

= Sales-Gross \ margin

On substituting the values, we get

= 400,000-120,000

= 280,000

As we know,

⇒ Cost \ of \ goods \ sold=Beginning \ inventory \ goods+ cost \ of \ goods \  manufactured-Ending \ inventory \ goods

⇒ 280,000=150,475+ cost \ of \ goods \ manufactured-145750

⇒ 280,000=cost \ of \ goods \ manufactured+4,725

⇒ Cost \ of \ goods \ manufactured=280,000-4,725

⇒                                                 =275,275 ($)

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Germanium forms a substitutional solid solution with silicon. Compute the number of germanium atoms per cubic centimeter for a g
brilliants [131]

Answer:

The number of germanium atoms per cubic centimeter for this germanium-silicon alloy is 3.16 x 10²¹ atoms/cm³.

Explanation:

Concentration of Ge (C_{Ge}) = 15%

Concentration of Si (C_{Si}) = 85%

Density of Germanium (ρ_{Ge}) = 5.32 g/cm³

Density of Silicon (ρ_{Si}) = 2.33 g/cm³

Atomic mass of Ge (A_{Ge})= 72.64 g/mol

To calculate the number of Ge atoms per cubic centimeter for the alloy, we will use the formula:

No of Ge atoms/cm³=[Avogadro's Number*C_{Ge}]/([C_{Ge}*A_{Ge}/ρ_{Ge})+(C_{Si}*A_{Ge}/ρ_{Si})]

                              = (6.02x10²³ * 15%) / [(15% * 72.64/5.32)+(72.64*85%/2.33)]

                              = (9.03x10²²)/(2.048+26.499)

                              = (9.03x10²²)/(28.547)

No of Ge atoms/cm³ = 3.16 x 10²¹ atoms/cm³

3 0
3 years ago
To be safe, the engineers making the ride want to be sure the normal force does not exceed 1.8 times each persons weight - and t
Yuri [45]

Answer:

μ = 0.55

Explanation:

Given that

Normal weight = 1.8 x weight of person

N= 1.8 mg

We know that friction force Fr

Fr= μ N

μ=Coefficient of friction

N=Normal force

To find  μ We have to equate friction and gravity force

Fr= Wt

μ N = m g

μ  x 1.8 m g = m g

μ = 0.55

So the coefficient of friction will be 0.55.

5 0
3 years ago
What are the rigging devices used to move loads such as steel plates and sheet piles without the use of slings, but grip the loa
scoundrel [369]

The rigging device which are used to move loads without the use of slings, but grip the load by biting down and using jaw tension to secure the load, is lifting clamps.

<h3>What are the rigging devices?</h3>

The rigging devices are used to lift the objects and items when the safety is required. This device is used in the industries.

Types of rigging devices

  • Rigging hooks-These rigging device is used when the heavy load need to be lift.
  • Lifting clamps-Lifting clamp are used to lift the device with jaw tension to secure the load. In this, there is no use of slings.
  • Pulley and blocks-In the load is lifts with the help of block and pulley arrangement. This is a widely used rigging device.

Thus, the rigging device which are used to move loads without the use of slings, but grip the load by biting down and using jaw tension to secure the load, is lifting clamps.

Learn more about the rigging devices here;

brainly.com/question/8430576

#SPJ1

4 0
2 years ago
The project's criteria.
Lena [83]

Answer: design 4

Explanation: I got it right

8 0
2 years ago
Ayuda!<br> es para mañana
ExtremeBDS [4]
No se ve la foto :( puedes a ser la pregunta otra ves?
8 0
3 years ago
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