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Julli [10]
3 years ago
5

using the following data for july, calculate the cost of goods manufactured: beginning finished goods inventory 150,475. Ending

finished goods inventory 145,750. sales 400,000. Gross Margin 120,000. The cost of goods manufactured was
Engineering
1 answer:
Alla [95]3 years ago
5 0

Answer:

The correct response is "$275,275".

Explanation:

The given values are:

Sales,

= 400,000

Gross margin,

= 120,000

Beginning Inventory goods,

= 150,475

Finished inventory goods,

= 145,750

Now,

The cost of goods sold will be:

= Sales-Gross \ margin

On substituting the values, we get

= 400,000-120,000

= 280,000

As we know,

⇒ Cost \ of \ goods \ sold=Beginning \ inventory \ goods+ cost \ of \ goods \  manufactured-Ending \ inventory \ goods

⇒ 280,000=150,475+ cost \ of \ goods \ manufactured-145750

⇒ 280,000=cost \ of \ goods \ manufactured+4,725

⇒ Cost \ of \ goods \ manufactured=280,000-4,725

⇒                                                 =275,275 ($)

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sp2606 [1]

Answer:

hello some parts of your question is missing attached below is the missing part

answer :

A) Determine changes in the 50-mm dimensions

The changes are : 0.006mm compression  in y-direction

                               0.002 mm expansion in x and z directions

B) the stress required are evenly distributed

Explanation:

<em>Given data</em> :

50-mm cube of graphite fiber reinforced polymer matrix

subjected to 125-KN force in direction 2,

direction 2 is perpendicular to fiber direction ( direction 1 ) and cube is constrained against expansion in direction 3

A) Determine changes in the 50-mm dimensions

The changes are : 0.006mm compression  in y-direction

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B) the stress required are evenly distributed

attached below is the detailed solution

4 0
3 years ago
Determine (a) the principal stresses and (b) the maximum in-plane shear stress and average normal stress at the point. Specify t
raketka [301]

Answer:

a) 53 MPa,  14.87 degree

b) 60.5 MPa  

Average shear = -7.5 MPa

Explanation:

Given

A = 45

B = -60

C = 30

a) stress P1 = (A+B)/2 + Sqrt ({(A-B)/2}^2 + C)

Substituting the given values, we get -

P1 = (45-60)/2 + Sqrt ({(45-(-60))/2}^2 + 30)

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Likewise P2 = (A+B)/2 - Sqrt ({(A-B)/2}^2 + C)

Substituting the given values, we get -

P1 = (45-60)/2 - Sqrt ({(45-(-60))/2}^2 + 30)

P1 = -68 MPa

Tan 2a = C/{(A-B)/2}

Tan 2a = 30/(45+60)/2

a = 14.87 degree

Principal stress

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b) Shear stress in plane

Sqrt ({(45-(-60))/2}^2 + 30) = 60.5 MPa

Average = (45-(-60))/2 = -7.5 MPa

5 0
3 years ago
What are the three elementary parts of a vibrating system?
zhenek [66]

Answer:

the three part are mass, spring, damping

Explanation:

vibrating system consist of three elementary system namely

1) Mass - it is a rigid body due to which system experience vibration and kinetic energy due to vibration is directly proportional to velocity of the body.

2) Spring -  the part that has elasticity and help to hold mass

3) Damping - this part considered to have zero mass and  zero elasticity.

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