Answer 1: minimum required flow rate of fresh air is 0.57 m^3/ses
Explanation: since the minimum requirement per person is 30 L/sec
Converting to m^3 it becomes
30/1000 = 0.03 m^3/sec
For 19 heavy smoker we will require
19 * 0.03 = 0.57m^3/sec
Answer 2: diameter of the duct will be 0.3m
Explanation: since flow rate is
Q =0.57m^3/sec
Also
Q = AV (continuity equation)
Where A is the duct area and V is the velocity of air flow in m/sec
0.57m^3/sec = A * 8m/sec
A = 0.57/8 = 0.071m^2
Area of the duct is that of a circle
A = 3.142 *(d^2 ÷4)
d^2 = (0.017 * 4)/3.142 = 0.09
d is square root of 0.09
d = 0.3m
Answer:
70.66 cm^3
The specific volume for P = 70.66 is within 1% of the experimental value while the viral equation will be inaccurate when the second viral coefficient is used )
Explanation:
Viral equation : Z = 1 + Bp + Cp^2 + Dp^3 + -----
Viral equation can also be rewritten as :
Z = 1 + B ( P/RT )
B ( function of time )
Temperature = 310 K
P1 = 8 bar
P2 = 75 bar
<u>Determine the specific volume in cm^3 </u>
V = 70.66 cm^3
<u>b) comparing the specific volumes to the experimental values </u>
70.58 and 3.90
The specific volume for P = 70.66 is within 1% of the experimental value while the viral equation will be inaccurate when the second viral coefficient is used )
attached below is the detailed solution
Economic cost is a rescission making tangible factor true
Answer:
f = 0.04042
Explanation:
temperature = 0°C = 273k
p = 600 Kpa
d = 40 millemeter
e = 10 m
change in P = 235 N/m²
μ = 2m/s
R = 188.9 Nm/kgk
we solve this using this formula;
P = ρcos*R*T
we put in the values into this equation
600x10³ = ρcos * 188.9 * 273
600000 = ρcos51569.7
ρcos = 600000/51569.7
=11.63
from here we find the head loss due to friction
Δp/pg = feμ²/2D
235/11.63 = f*10*4/2*40x10⁻³
20.21 = 40f/0.08
20.21*0.08 = 40f
1.6168 = 40f
divide through by 40
f = 0.04042
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