What do u need? Rusbaisuwvwbs
Answer:
16 seconds
Explanation:
Given:
C = 60
L = 4 seconds each = 4*4 =16
In this problem, the first 3 timing stages are given as:
200, 187, and 210 veh/h.
We are to find the estimated effective green time of the fourth timing stage. The formula for the estimated effective green time is:
Let's first find the fourth stage critical lane group ratio
, using the formula:


Solving for
, we have:
Let's also calculate the volume capacity ratio X,

X = 0.704
For the the estimated effective green time of the fourth timing stage, we have:
Substituting figures in the equation, we now have:
15.78 ≈ 16 seconds
The estimated effective green time of the fourth timing stage is 16 seconds
Answer:
the flow is turbulent
Explanation:
The Reynolds number is given by
Re=ρVD/μ
where
V=fluid speed=0.48ft/s=0.146m/s
D=diameter=2.067in=0.0525m
ρ=density=0.805g/cm^3=805Kg/m^3
μ=0.43Cp=4.3x10^-4Pas
Re=(805)(0.146)(0.0525)/4.3x10^-4=14349.59
Re>2100 the flow is turbulent
Note: if you do not want to use a calculator you can use the graphs to calculate the Reynolds number according to their properties
Answer:
The movement performed is the gun of manual Submerged Arc Welding.
Explanation:
Submerged Arc Welding is a type of welding process which is used for the joining of similar as well as dissimilar metals. The arc is produced between the electrode and workpiece that has to be joined. The heat produced due to this arc is used for joining these metals. The fusion forms a molten pool and is protected by using a thick layer of flux or sla g from the atmosphere. This molten flux or sla g is formed by the granular fluxing.
Answer:
<em>Cout = 11mg/L</em>
Explanation:
Assume Steady State and CSTR, this means Qin = Qout
Given: Qin = 4 000m3/day
Cin = 25mg/L
V = 20 000m3
k = 0.25/day
Find: Cout = ?
outStarting from the mass balance equation for steady state 0 = QCin - QCout - kCoutV
manipulate the equation to get:
\(Cout=Cin(Q/Q+kV)\)
<em>Then simple plug in your givens:
</em>
<em>Cout = (25mg/L)((4000m3/day)/(4000m3/day + 0.25/day(20000m3))
</em>
<em>Cout = 11mg/L</em>