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weqwewe [10]
3 years ago
12

What unit is used to measure the period of a wave?

Physics
1 answer:
mixer [17]3 years ago
4 0

Answer:

D. Meters/Seconds

Explanation:

The time period of a wave is measured in seconds.

A typical wave involves both time and distance.  Consider a sound wave, which is basically a periodic modulation of the local air pressure.  We "hear" the sound because our ears respond to the variations of pressure.

The most common metric of a sound wave is frequency.  This is the rate at which the change in pressure occurs, and is measured in cycles per second, formally known as "hertz".  The period is the inverse of frequency andl has the units of seconds per cycle, commonly stated simply as seconds.

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How are the concepts of impulse and momentum related?
butalik [34]

Answer:

The impulse experienced by the object equals the change in momentum of the object. In equation form, F • t = m • Δ v. In a collision, objects experience an impulse; the impulse causes and is equal to the change in momentum. ... The collision would change the halfback's speed and thus his momentum.

Explanation:

4 0
3 years ago
A solid sphere has a radius of 0.200 m and a mass of 150.0 kg. how much work is required to get the sphere rolling with an angul
Allisa [31]

Here in this case we can use work energy theorem

As per work energy theorem

Work done by all forces = Change in kinetic Energy of the object

Total kinetic energy of the solid sphere is ZERO initially as it is given at rest.

Final total kinetic energy is sum of rotational kinetic energy and translational kinetic energy

KE = \frac{1}{2}Iw^2 +\frac{1}{2} mv^2

also we know that

I = \frac{2}{5}mR^2

w= \frac{v}{R}

Now kinetic energy is given by

KE = \frac{1}{2}(\frac{2}{5}mR^2)w^2 +\frac{1}{2} m(Rw)^2

KE = \frac{1}{5}mR^2w^2 +\frac{1}{2} mR^2w^2

KE = \frac{7}{10}mR^2w^2

KE = \frac{7}{10}*150*(0.200)^2(50)^2

KE = 10500 J

Now by work energy theorem

Work done = 10500 - 0 = 10500 J

So in the above case work done on sphere is 10500 J

7 0
3 years ago
Need help with exercises 3,4,5<br><br> Will give brainliest!!!
Harman [31]

I pretty sure that 3 is b and 4 is A and 5 I need a full picture

4 0
4 years ago
A physics student skis down a hill, accelerating at a constant
ikadub [295]
<h3>Answer:</h3>

225 meters

<h3>Explanation:</h3>

Acceleration is the rate of change in velocity of an object in motion.

In our case we are given;

Acceleration, a = 2.0 m/s²

Time, t = 15 s

We are required to find the length of the slope;

Assuming the student started at rest, then the initial velocity, V₀ is Zero.

<h3>Step 1: Calculate the final velocity, Vf</h3>

Using the equation of linear motion;

Vf = V₀ + at

Therefore;

Vf = 0 + (2 × 15)

    = 30 m/s

Thus, the final velocity of the student is 30 m/s

<h3>Step 2: Calculate the length (displacement) of the slope </h3>

Using the other equation of linear motion;

S = 0.5 at + V₀t

We can calculate the length, S of the slope

That is;

S = (0.5 × 2 × 15² ) - (0 × 15)

= 225 m

Therefore, the length of the slope is 225 m

6 0
3 years ago
What happens to electric charges within a conductor when a charged object is brought close to it
Agata [3.3K]
Well, if a charger conductor is touched to another object or close enough to touching the object then the conductor can transfer its charge to that object. Conductors allow for electrons to be transported from particle to particle, so a charged object will always distribute its charge until the repulsive forces are minimized.
8 0
4 years ago
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