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Elan Coil [88]
2 years ago
10

What is the current of the ammeter?

Physics
2 answers:
DaniilM [7]2 years ago
3 0

Answer:

.6 A

Explanation:

V = IR

V/R = I

12/20 = I = .6 A

Bumek [7]2 years ago
3 0

Answer:

a) 0.60 A

Explanation:

Given that,

→ Potential difference (V) = 12 V

→ Resistance (R) = 20 Ω

→ Current (I) = ?

Formula we use,

→ I = V/R

Let's solve the problem,

→ I = V/R

→ I = 12/20

→ [ I = 0.60 ]

Hence, option (a) is the answer.

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Vaselesa [24]
Using KE=1/2mv^2

v=\sqrt{50000/500

so v=10
3 0
3 years ago
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A cylindrical tank has a tight-fitting piston that allows the volume of the tank to be changed. The tank originally contains 0.1
Stolb23 [73]

Answer:

it could be 69

Explanation:

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3 years ago
If a car is accelerating downhill under a net force 3674 N , what additional force would cause the car to have a constant veloci
Semenov [28]

Answer:

For the car to move with constant velocity the additional force required is  F__{dg} }=  -3674 \  N

Explanation:

From the question we are told that

  The net force of the car is  F_{net} = 3674 \  N

Generally the total  force acting on the  car is the net force plus the force due to gravity acting in direction of the car (Let denote it as F__{dg})

So the total force acting on the car is mathematically represented as

        F_{net} + F__{dg}} = F

Here this F representing the total force can be mathematically represented as

      F =  ma

Now for constant velocity to be attained, the acceleration of the car will be zero  

So  at constant velocity

       F =  m * 0

=>    F =   0 \  N

So  

     F_{net} + F__{dg}} = 0

=>   F__{dg} }=  -F_{net}

=>   F__{dg} }=  -3674 \  N

6 0
2 years ago
2 types of energy transformations that take place in a race car during a race?​
vichka [17]

Answer:

Explanation:

Chemical to thermal as fuel is burned

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4 0
2 years ago
How much work does a man perform on a lawnmower if he applies 25 N of force to push it 100 meters
zmey [24]
  • Force=25N
  • Displacement=100m

\\ \sf\longmapsto Work\:Done=Force\times Displacement

\\ \sf\longmapsto Work\:Done=25(100)

\\ \sf\longmapsto Work\:Done=2500J

3 0
3 years ago
Read 2 more answers
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