Answer:
a = 2.5 [m/s²]
Explanation:
To solve this problem we must use the following equation of kinematics.
where:
Vf = final velocity = 25 [m/s]
Vo = initial velocity = 0 (star from the rest)
a = acceleration [m/s²]
t = time = 10 [s]
25 = 0 + (a*10)
a = 25/10
a = 2.5 [m/s²]
0.520155077123917 i believe?? hope this helps
Answer:
w = √[g /L (½ r²/L2 + 2/3 ) ]
When the mass of the cylinder changes if its external dimensions do not change the angular velocity DOES NOT CHANGE
Explanation:
We can simulate this system as a physical pendulum, which is a pendulum with a distributed mass, in this case the angular velocity is
w² = mg d / I
In this case, the distance d to the pivot point of half the length (L) of the cylinder, which we consider long and narrow
d = L / 2
The moment of inertia of a cylinder with respect to an axis at the end we can use the parallel axes theorem, it is approximately equal to that of a long bar plus the moment of inertia of the center of mass of the cylinder, this is tabulated
I = ¼ m r2 + ⅓ m L2
I = m (¼ r2 + ⅓ L2)
now let's use the concept of density to calculate the mass of the system
ρ = m / V
m = ρ V
the volume of a cylinder is
V = π r² L
m = ρ π r² L
let's substitute
w² = m g (L / 2) / m (¼ r² + ⅓ L²)
w² = g L / (½ r² + 2/3 L²)
L >> r
w = √[g /L (½ r²/L2 + 2/3 ) ]
When the mass of the cylinder changes if its external dimensions do not change the angular velocity DOES NOT CHANGE
Voltage = (current) x (resistance)
Voltage = (4.00 A) x (330 Ω)
<em>Voltage = 1,320 V (D)</em>
Answer:
counterclockwise
Explanation:
= Small drive wheel radius = 2.2 cm
= Angular acceleration of the small drive wheel = 
= Radius of pottery wheel = 28 cm
= Angular acceleration of pottery wheel
As the linear acceleration of the system is conserved we have
The angular acceleration of the pottery wheel is .
The rubber drive wheel is rotating in clockwise direction so the pottery wheel will rotate counterclockwise.
= Initial angular velocity = 0
= Final angular velocity = 
t = Time taken
From the kinematic equations of linear motion we have
The time it takes the pottery wheel to reach the required speed is
