A plane coming in to land at a busy airport is asked to circle the airport until the air traffic congestion eases off. The pilot
keeps the plane at the approved altitude and in a circle of constant radius of 1.99 ✕ 104 m. If the speed of the plane is 185 m/s (around 414 mph), at what angle are the plane's wings banked from the horizontal? Note that the lift force on the wings is always perpendicular to the wings. (Give an angle between 0 and 90 degrees.)
1 answer:
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Answer:
period of oscillations is 0.695 second
Explanation:
given data
mass m = 0.350 kg
spring stretches x = 12 cm = 0.12 m
to find out
period of oscillations
solution
we know here that force
force = k × x .........1
so force = mg = 0.35 (9.8) = 3.43 N
3.43 = k × 0.12
k = 28.58 N/m
so period of oscillations is
period of oscillations = 2π × ................2
put here value
period of oscillations = 2π ×
period of oscillations = 0.6953
so period of oscillations is 0.695 second