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MariettaO [177]
3 years ago
11

A plane coming in to land at a busy airport is asked to circle the airport until the air traffic congestion eases off. The pilot

keeps the plane at the approved altitude and in a circle of constant radius of 1.99 ✕ 104 m. If the speed of the plane is 185 m/s (around 414 mph), at what angle are the plane's wings banked from the horizontal? Note that the lift force on the wings is always perpendicular to the wings. (Give an angle between 0 and 90 degrees.)

Physics
1 answer:
Ber [7]3 years ago
8 0

Answer:

The solution is given in the picture attached below

Explanation:

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Consider a Hydrogen atom with the electron in the n 8 shell. What is the energy of this system? (The magnitude of the ground sta
Shtirlitz [24]

Answer:

The energy of an electron in the 8th shell is given by:  -0.2125 eV

The number of subshells is:  8

The number of orbitals is:  64

The number of electrons that fit on this shell is: 128

Explanation:

First, we find the energy of the electrons in the 8th shell. In order to do this, we recall that the energy of an electron (in the Hydrogen atom) whose principal number is n is given by:

E_{n}=-13.6\frac{1}{n^{2}}

Substituting n=8, we find that the energy is given by:

E_{8} = -13.6\frac{1}{8^{2}}=-0.2125

In order to find the number of subshells we recall that, for a given principal quantum number n, the possible values of the quantum number l, which corresponds to the number of subshells are:

0, 1, 2, ... , n-1

Since n = 8 in our problem, the possible values of l are: 0, 1, 2, 3, 4, 5, 6, 7. Therefore, the number of subshells are 8.

Now we continue with the number of orbitals. For every subshell l, we have 2l+1 possible values of m, which correspond to the orbitals. Since the possible values of l are: 0,1,2,3,4,5,6,7, therefore, we have to perform the sum:

\sum_{l=0}^{7}(2l+1) = 8^2=64

And we can conclude that the number of orbitals is equal to 64.

Finally, we know that we can fit two electrons per orbital, therefore we can have 64*2 = 128 electrons in the shell corresponding to n=8.

8 0
4 years ago
What is 3,278,000 as scientific notation?
jonny [76]
3.278*10^6 I think. Sorry if it’s wrong.
4 0
3 years ago
Increase the slit width to 1050 nm. What happens to the width of the central bright fringe? (Always remember to wait a few secon
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Answer:

b.

Explanation:

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Then In Single slit Diffraction, width of central fringe is

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a= slit width

\lambda = wavelength

Thus if Screen width increases keeping other factors same then width of central fringe becomes narrower as

x_c\propto 1/a

On increasing the slit width the central bright fringe width The width of the central bright fringe becomes narrower.

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What happens to a wave when it moves from one medium to another?
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3 years ago
PLEASE HELP FAST
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a. Independent variable:   <em>TIME </em>

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