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3 years ago

Of all the mutations, we can conclude that one mutation would MOST LIKELY contribute to a rapid rate of

Physics

2 answers:

raketka [301]3 years ago

7 0

Answer:

A) blindness

Explanation:

Harlamova29_29 [7]3 years ago

3 0

Answer:

D) fused hands, no range of motion.

Explanation:

As we've seen in blind people, blindness is adapted to and other skills are highly developed to accommodate. B would be awkward, but not deadly. C would be fine mostly, since we are still able to see. However, D, with no range of motion, we would find it very difficult to defend ourselves and care for ourselves.

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A pipe is open at both ends. The pipe has resonant frequencies of 528 Hz and 660HZ (among others).

yawa3891 [41]

To develop this problem it is necessary to apply the oscillation frequency-related concepts specifically in string or pipe close at both ends or open at both ends.

By definition the oscillation frequency is defined as

$f = n\frac{v}{2L}$

Where

v = speed of sound

L = Length of the pipe

n = any integer which represent the number of repetition of the spectrum (n)1,2,3...)(Number of harmonic)

Re-arrange to find L,

$f = n\frac{v}{2L}\\L = \frac{nv}{2f}$

The radius between the two frequencies would be 4 to 5,

$\frac{528Hz}{660Hz}= \frac{4}{5}$

$4:5$

Therefore the frequencies are in the ratio of natural numbers. That is

$4f = 528\\f = \frac{528}{4}\\f = 132Hz$

Here f represents the fundamental frequency.

Now using the expression to calculate the Length we have

$L = \frac{nv}{2f}\\L = \frac{(1)343m/s}{2(132)}\\L = 1.29m$

Therefore the length of the pipe is 1.3m

For the second harmonic n=2, then

$L = \frac{nv}{2f}\\L = \frac{(2)343m/s}{2(132)}\\L = 2.59m$

Therefore the length of the pipe in the second harmonic is 2.6m

7 0

3 years ago

Water flowing through a cylindrical pipe suddenly comes to a section of pipe where the diameter decreases to 86% of its previous

Orlov [11]

Answer:

Explanation:

The speed of the water in the large section of the pipe is not stated

so i will assume 36m/s

(if its not the said speed, input the figure of your speed and you get it right)

Continuity equation is applicable for ideal, incompressible liquids

Q the flux of water that is Av with A the cross section area and v the velocity,

so,

$A_1V_1=A_2V_2$

$A_{1}=\frac{\pi}{4}d_{1}^{2} \\\\ A_{2}=\frac{\pi}{4}d_{2}^{2}$

the diameter decreases 86% so

$d_2 = 0.86d_1$

$v_{2}=\frac{\frac{\pi}{4}d_{1}^{2}v_{1}}{\frac{\pi}{4}d_{2}^{2}}\\\\=\frac{\cancel{\frac{\pi}{4}d_{1}^{2}}v_{1}}{\cancel{\frac{\pi}{4}}(0.86\cancel{d_{1}})^{2}}\\\\\approx1.35v_{1} \\\\v_{2}\approx(1.35)(38)\\\\\approx48.6\,\frac{m}{s}$

Thus, speed in smaller section is 48.6 m/s

3 0

3 years ago

I need someone to help on this number!

Artist 52 [7]

Radioactive decay in the core releases energy. When the sun matter is heated it reduced in density and rises to the surface of the sun, meaning the energy is transferred to the surface.

6 0

4 years ago

One alternative to burning non-renewable fuels, which harm the environment, could be to burn?

Rashid [163]

Answer:

The answer to that is C. natural gas

3 0

3 years ago

Read 2 more answers

A child of mass 51.9 kg sits on the edge of a merry-go-round with radius 2.4 m and moment of inertia 215.24 kg m2 . The merry go

aalyn [17]

Answer:

4.25 rad/s

Explanation:

Given that.

Mass, m = 51.9 kg

Radius, r1 = 2.4 m

Moment of inertia, I = 215.24 kgm^2

Angular velocity, ω = 2.1 rad/s

Radius, r2 = 0.864 m

To start with, we are going to use the Conservation of angular momentum to solve the question, which is

l(initial) = l(final)

[I₁ + I₂](initial)*ω(initial) = [I₁ + I₂](final)*ω(final)

Making ω(final) the subject of formula, we have

ω(final) = [I₁ + I₂](initial)*ω(initial) / [I₁ + I₂](final)

ω(final) = [215.24 + (51.9)(2.4)²](2.1) / [215.24 + (51.9)(0.864)²]

ω(final) = [215.24 + 298.944]2.1 / [215.24 + 38.74]

ω(final) = 514.184 * 2.1 / 253.98

ω(final) = 1079.786 / 253.98

ω(final) = 4.25 rad/s

= 5.273 rad/s

7 0

3 years ago