Answer:
r₂ = 0.316 m
Explanation:
The sound level is expressed in decibels, therefore let's find the intensity for the new location
β = 10 log
let's write this expression for our case
β₁ = 10 log \frac{I_1}{I_o}
β₂ = 10 log \frac{I_2}{I_o}
β₂ -β₁ = 10 (
)
β₂ - β₁ = 10
log \frac{I_2}{I_1} =
= 3
= 10³
I₂ = 10³ I₁
having the relationship between the intensities, we can use the definition of intensity which is the power per unit area
I = P / A
P = I A
the area is of a sphere
A = 4π r²
the power of the sound does not change, so we can write it for the two points
P = I₁ A₁ = I₂ A₂
I₁ r₁² = I₂ r₂²
we substitute the ratio of intensities
I₁ r₁² = (10³ I₁ ) r₂²
r₁² = 10³ r₂²
r₂ = r₁ / √10³
we calculate
r₂ =
r₂ = 0.316 m

Where r is the radius of balloon.
Here mass of woman = 68 kg
Mass of air displaced by a balloon with volume V = 1.29*V
Mass of helium inside balloon = 0.178*V
Total mass to be lifted by balloon = 68 +0.178*V
Buoyant force = 1.29V-0.178V=1.112V
So we have 1.112 V = 68+ 0.178*V
0.934 V = 68
V = 72.81 
\frac{4}{3} \pi r^{3}[/tex]= 72.81
r = 2.59 m
So radius of helium balloon = 2.59 m
The North America will not be able to view the eclipse because of its location on the earth caused by the tilting of the earth.
<h3>
Effect of tilting of the Earth</h3>
The tilt of the Earth is what causes seasons to occur. These are the seasons in relation to the Northern Hemisphere.
The tilting of the Earth causes the difference in the amount of sun reaching each region of the earth like in the North America continent.
Thus, the North America will not be able to view the eclipse because of its location on the earth caused by the tilting of the earth.
Learn more about eclipse here: brainly.com/question/8643
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The answer is C. p=mv p=18x30 = 540kgm/s
Hi there!
We can begin by deriving the equation for how long the ball takes to reach the bottom of the cliff.

There is NO initial vertical velocity, so:

Rearrange to solve for time:

Plug in the given height and acceleration due to gravity (g ≈ 9.8 m/s²)

Now, use the following for finding the HORIZONTAL distance using its horizontal velocity:
