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Over [174]
3 years ago
10

The gases carbon dioxide, oxygen, and argon are mixed in a container. All gases have the same partial pressure, and the total pr

essure of the container is 32,680 Pa. What is the partial pressure of argon ?
Chemistry
1 answer:
polet [3.4K]3 years ago
4 0
The partial pressure of argon can be calculated simply by dividing the total pressure by 3. This gives an answer equivalent to 10893.33 Pa. The clue behind this is the statement "a<span>ll gases have the same partial pressure". This follows Dalton's Law of Partial Pressures which states that the total pressure is equal to the sum of the individual partial pressures.</span>
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Solve and show work. Li2S + 2 HNO3 --&gt; 2 LiNO3 + H2S (a) Calculate the mass of lithium sulfide that will react with 250 mL of
Elenna [48]

Li2S + 2 HNO3 --> 2 LiNO3 + H2S

Li2 S  +   H2 N2 O2  -->   Li2 N2 O5   +   H2 S

Li S + H2 N2 O5 -> Li N2 O5 + H2 S

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3 years ago
The colour change of methyl orange with neutral substance​
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Answer:

Pink

Explanation:

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3 0
4 years ago
Dalton hypothesesized that atoms are indivisible and that all atoms of an element are identical. it is now known that
Katena32 [7]

i don't understand but atoms are made of electrons an protons and neutrons..

6 0
3 years ago
Someone please help me and answer my question asap. i need to turn my assignment in soon... please.
Ksenya-84 [330]

Answer:

Explanation:

a. the salt produced would be Mg3N2(magnesium nitride)

b. magnesium loses 2 electron to form Mg2+ ion and nitrogen gains 3 electron to form n3-

when several of these ions come together 3 Mg2+ ion combine with 2 n3- ion to form Mg3N2 thus Mg getting six electron from nitrogen to form a ionic bond.

c. the reaction is not balanced Mg + N2 = Mg3n2

to make it balanced the reaction should be 3 Mg + N2 = Mg3N2.

the reaction was not balanced before because the number of Mg on both side of the reaction was not equal.

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8 0
3 years ago
Some fertilizer blends contain magnesium nitrate (MgNO3). Suppose that a chemist has 1.24 liters of a 2.13 M solution of magnesi
tamaranim1 [39]

Initial concentration of magnesium nitrate M1 = 2.13 M

Initial volume of magnesium nitrate, MgNO3  V1 = 1.24 L

Final concentration of MgNO3, M2 = 1.60 M

Let the final volume of MgNO3 upon dilution be V2

Formula to use:

M1*V1 = M2*V2

V2 = M1*V1/M2

      = 2.13 M * 1.24 L/1.60 M = 1.65 L

Thus, the final volume of magnesium nitrate solution upon dilution is 1.65 L

7 0
3 years ago
Read 2 more answers
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