A brick is lying on a table in a state of static equilibrium. If the mass of the brick is 7.52 kilograms, what is the normal for
ce exerted by the table on the brick?
1 answer:
Answer:
-mg = -7.52*9.8 = - 73.696N
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Answer:
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Answer:
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Electric field = potential difference
-----------------------------
distance between plates
Distance between plates = 45
----------
500
= 0.09 meters.
Answer:
a = 2m/s^2
Explanation:
Force (F) = 100 N
Mass (m) = 50 kg
Here,
F = m×a
100 = 50 × a
a = 100÷50
a = 2m/s^2
Thus, the acceleration on the cart is a = 2m/s^2
-TheUnknownScientist
