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2 years ago

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A brick is lying on a table in a state of static equilibrium. If the mass of the brick is 7.52 kilograms, what is the normal for

ce exerted by the table on the brick?

1 answer:

WARRIOR [948]2 years ago

7 0

Answer:

-mg = -7.52*9.8 = - 73.696N

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James gently releases a ball at the top of a slope But does not push the ball. Space the ball rolls down the slope. Which force

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Which best describes why scientific models change over time?

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3 years ago

Coherent light of frequency 6.37×1014 Hz passes through two thin slits and falls on a screen 88.0 cm away. You observe that the

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Answer:

The distance between the two slits is 40.11 μm.

Explanation:

Given that,

Frequency $f= 6.37\times10^{14}\ Hz$

Distance of the screen l = 88.0 cm

Position of the third order y =3.10 cm

We need to calculate the wavelength

Using formula of wavelength

$\lambda=\dfrac{c}{f}$

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Put the value into the formula

$\lambda=\dfrac{3\times10^{8}}{6.37\times10^{14}}$

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$m\times \lambda=d\sin\theta$

$d =\dfrac{m\times\lambda}{\sin\theta}$

Where, m = number of fringe

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Here, $\sin\theta =\dfrac{y}{l}$

Put the value into the formula

$d=\dfrac{3\times471\times10^{-9}\times88.0\times10^{-2}}{3.10\times10^{-2}}$

$d=40.11\times10^{-6}\ m$

$d = 40.11\ \mu m$

Hence, The distance between the two slits is 40.11 μm.

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2 years ago