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3 years ago

If the fundamental frequency of a violin string is 440 HzHz, what is the frequency of the second harmonic?

Physics

1 answer:

tino4ka555 [31]3 years ago

7 0

Answer:

880Hz

Explanation:

A violin string is an example of an open pipe. An open pipe is open at both ends.

The fundamental frequency is the first harmonic.In an open pipe the second harmonic is twice the fundamental frequency.

Hence, second harmonic = 2Fo

Fo=440Hz

Second harmonic = 2*440Hz

Second harmonic = 880Hz

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an object weighting 100g is thrown upwards from the ground at a speed of 100 m/s.where will the potential energy of the object b

Kay [80]

Answer:

333.3 m

Explanation:

Given

$m =100g\ =\ 0.1kg\\v = 100 m/s\\g = 10 m/s ^2$

Potential energy = $\frac{2}{3}\ of\ Kinetic\ energy$ ......Equation(1)

We know that

Potential energy=mgh

Kinetic energy = $\frac{1}{2} mv^{2}$

Now From the Equation(1)

$mgh=\frac{2}{3}*\frac{1}{2} mv^{2}\\ gh=\frac{v^{2} }{3} \\10 * h=\ \frac{10000}{3}\\ h=\ \frac{1000}{3} \\h=333.3\ m$

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3 years ago

a bus is moving at 22m/s [E] for 12s. Then the bus driver slows down at 1.2m/s2 [W] until the bus stops. Determine the total dis

KatRina [158]

The total displacement is equal to the total distance. For the east or E direction, the distance is determined using the equation:

d = vt = (22 m/s)(12 s) = 264 m

For the west or W direction, we use the equations:
a = (v - v₀)/t
d = v₀t + 0.5at²

Because the object slows down, the acceleration is negative. So,
-1.2 m/s² = (0 m/s - 22 m/s)/t
t = 18.33 seconds
d = (22 m/s)(18.33 s) + 0.5(-1.2 m/s²)(18.33 s)²
d = 201.67 m

Thus,
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3 years ago

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mart [117]

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What change will always result in an increase in gravitational force between two objects

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3 years ago

Which law of motion accounts for the following statement?

strojnjashka [21]

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3 years ago

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