Answer:
A 75.1 N and a direction of 152° to the vertical.
B 85.0 N at 0° to the vertical.
Explanation:
A) The interaction partner of this normal force has what magnitude and direction?
The interaction partner of this normal force is the component of the weight of the crate perpendicular to the ramp. <u>It has a magnitude of 85cos28° = 75.1 N and a direction of 180° - 28° = 152° to the vertical(since it is directed downwards perpendicular to the ramp).</u>
B) The normal and frictional forces are perpendicular components of the contact force exerted on the crate by the ramp. What is the magnitude and direction of the contact force?
Since this force has to balance the weight of the crate, its magnitude is 85.0 N. Its direction has to be vertically opposite to that of the weight.
Since the weight is 180° to the vertical (since it is directed downwards), this force is 0° to the vertical.
<u>So, this force has a magnitude of 85.0 N and a direction of 0° to the vertical.</u>
A person is submerged of about 97.9%.
The average density of the human body is given as 979 kg/ m³.
<h3>Define Law of floatation.</h3>
Law of floatation can be defined as the volume of the liquid displaced when a body floats on the liquid surface is equal to the body submerged in the water.
As body has the stable equilibrium state, the buoyancy of the fluid will be equal to the weight.
Weight of the body floating = Weight of the body immersed in fluid
Law of floatation = Density of the floating object / density of fluid
As fluid is the freshwater here, the density of fluid will be 1000 kg/ m³.
= (979 kg/ m³) / ( 1000 kg/ m³)
= 97.9 %
A person is submerged when floating gently in fresh water about 97.9%.
Learn more about law of floatation,
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The material of density 7.8 g/cm³
Explanation:
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