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3 years ago

14

Relate RNA to translation and transcription

1 answer:

vlabodo [156]3 years ago

4 0

Answer:

RNA plays a role in both Translation and transcription.

Explanation:

RNA translation uses mRNA (or messenger RNA) in order to bring the coding to the ribosome.

RNA transcription is where the coding receives a new strand of coding (replacing thymine with uracil) , which is then turned into protein

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I need help on 7 &8

Anettt [7]

I believe it’s a then d

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3 years ago

What is the magnification of an astronomical telescope whose objective lens has a focal length of 71 cm and whose eyepiece has a

Rus_ich [418]

To solve this problem it is necessary to apply the concepts related to optical magnification (is the process of enlarging the apparent size, not physical size, of something.). Specifically the angular magnification of an optical telescope is given by

$M = -\frac{f_o}{f_e}$

Where,

$f_o =$ Focal length of the objective lens in a refractor

$f_e =$ Focal length of the eyepiece

Our values are given as

$f_o =$ 71cm

$f_e =$ 2.1cm

Replacing we have

$M = -\frac{f_o}{f_e}$

$M = -\frac{71}{2.1}$

$M = - 33.81$

Therefore the magnification of this astronomical telescope is -33.81

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3 years ago

WHICH TYPES OF ENERGY ARE HAPPENING

Lady bird [3.3K]

Answer:

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Explanation:

................

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4 years ago

9. A wave on Beaver Dam Lake passes by two docks that are 40.0 m apart.

Kobotan [32]

Answers:

a) 10 m

b) time=1.6 s, frquency=0.625 Hz

c) 6.25 m/s

Explanation:

a) If there is a crest at each dock and another three crests between the two docks, and the wavelength $\lambda$ is the distance between to crests; this means we have $4\lambda$ in $40 m$ :

$40 m=4\lambda$

Clearing $\lambda$ :

$\lambda=\frac{40 m}{4}$

$\lambda=10 m$

b) This part can be solved by a Rule of Three:

If 10 waves ---- 16 s

1 wave ----- $T$

Then:

$T=\frac{(1 wave)(16 s)}{10 waves}$

$T=1.6 s$ This is the period of the wave

On the other hand, the frequency $f$ of the wave has an inverse relation with its period $T$ :

$f=\frac{1}{T}$

$f=\frac{1}{1.6 s}$

$f=0.625 Hz$ This is the frequency of the wave

c) The speed $v$ of a wave is given by the following equation:

$v=\frac{\lambda}{T}$

$v=\frac{10 m}{1.6 s}$

Finally:

$v=6.25 m/s$

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3 years ago

Choose ALL of the answers that would support the theory of Continental Drift?

saveliy_v [14]

The answers are B, D, E!

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3 years ago

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