Answer:
emf induced in the loop, at the instant when 9.0s have passed = 1.576 * 10 ⁻² V.
Direction is counter clockwise.
Explanation:
See attached pictures.
Answer:
So as KE becomes 4times , Momentum will increase by 2 times.
Answer:
The correct wording is
- Pressure increases with the depth of the fluid.
- A plane's engines produce thrust to push the plane forward.
- A fluid can be a liquid or a gas.
- A hydraulic device uses Pascal's principle to lift or move objects.
- lift is the upward force exerted on objects by fluids.
Explanation:
1. As you go deeper into a fluid,<em> there is more of it on top of you; </em>therefore, the pressure excreted on you is greater.
2. A plane's engines pushes the air in opposite direction, which according to newton's third law, produces necessary force to move the plane forward.
3. <em>A fluid has no fixed shape,</em> and it deforms under the influence of external forces applied—liquid and gases fit into this definition.
4. Pascal's principle <em>says that pressure applied on one region of the fluid must equal pressure transmitted to another region of the same fluid</em>. This principle is used in a hydraulic device to exert forces on fluids to lift objects that would otherwise be difficult to move.
5. By definition, the upward force exerted by the fluids on objects is the lift.
The electric field due to a point charge of 20uC at a distance of 1 meter away from it is 180000
.
First, you have to know that the space surrounding a load suffers some kind of disturbance, since a load located in that space will suffer a force. The disturbance that this charge creates around it is called an electric field.
In other words, an electric field exists in a certain region of space if, when introducing a charge called witness charge or test charge, it undergoes the action of an electric force.
The electric field E created by the point charge q at any point P, located at a distance r, is defined as:

where K is the constant of Coulomb's law.
In this case, you know:
- K= 9×10⁹

- q= 20 uC=20×10⁻⁶ C
- r= 1 m
Replacing in the definition of electric field:

Solving:
<u><em>E=180000 </em></u>
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Finally, the electric field due to a point charge of 20uC at a distance of 1 meter away from it is 180000
.
Learn more:
Answer: e = 3.333% or 33 1/3%
^
repeated
Identify the given information.
Work input (Wi)= 600 K
Work output (Wo) = 200 K
Choose which formula you should use. In this case, you are finding efficiency.
e = (Wo/Wi) x 100%
Substitute and solve.
e = (200 K/600 K) X 100%
e = 0.333 X 100%
e = 33.333% or 33 1/3%