Answer:
163 kilograms per cubic feet.
Explanation:
To solve this problem, first we <u>convert 5.77 g/cm³ to kg/cm³</u>:
- 5.77 g/cm³ *
= 5.77x10⁻³ kg/cm³
Then we <u>convert kg/cm³ to kg/ft³</u>, by <em>converting cm³ to ft³</em>:
- 5.77x10⁻³ kg/cm³ *
= 163 kg/ft³
So the density is 163 kilograms per cubic feet.
Answer:
0.45 moles
Explanation:
1 mole of gas at s.t.p gives 22.4dm3 when converted to litre it will be 22.4l/ x mole of N2 will give 10.0l the answer is equal to 0.45mole
Answer:
The answer to your question is: letter B
Explanation:
The information given is showing us three kinds of carbons and their respective number of protons and neutrons. Now, let's analize the options given:
A.)Carbon Bond Types This option is about trhe kind of bonds carbon is able to form like single, double or triple and is different from the information descrive above. So ,this option is incorrect.
B.)Carbon Isotopes is option is about the carbon atoms that have the same number of protons and different amount of neutrons exactly as it is describe above, to this option is correct.
C.)The Carbon Cycle
this option is about how carbon goes from one kind of matter to another and is completely different to the description given above, so this option is incorrect.
D.)Chemical Reactions this option is about reactants that after a process give products they could be from carbon -12, carbon-13 or carbon-14 and other elements, so this option is different from the description given above.
Answer:
seven on the ph scale is the neutral point
Explanation:
The range goes from 0 - 14, with 7 being neutral. pHs of less than 7 indicate acidity, whereas a pH of greater than 7 indicates a base. pH is really a measure of the relative amount of free hydrogen and hydroxyl ions in the water.
Answer:
The answer to your question is: 16.7 g of KBr
Explanation:
Data
mass KBr = ? g
Volume = 0.400 L
Concentration = 0.350 M
Formula
Molarity = moles / volume
moles = molarity x volume
Process
moles = (0.350)(0.400)
= 0.14
MW KBr = 39 + 80 = 119 g
119 g of KBr -------------------- 1 mol
x -------------------- 0.14 mol
x = (0.14 x 119) / 1
x = 16.7 g of KBr