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Furkat [3]
3 years ago
8

A sample of carbon monoxide gas is initially in a 5858 mL container. The gas is then moved to 3.29 L container at a temperature

of 195 °C. Determine the initial temperature of the gas in kelvin. Round your answer to three significant figures. Include the unit in your answer.
Chemistry
1 answer:
Doss [256]3 years ago
5 0

Answer:

d i took the test

Explanation:

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Help and show work please
olya-2409 [2.1K]
ANWERS ~
We know that :
1 cal (th) = 4.184 J
1 J = 0.2390057361 cal (th) , so :

•55.2 j to cal > 13.193116635 cal
•110 call > 460.24 joule
•65 kj > divide the energy value by 4.184
= 15.535 kilocalories calorie (IT)
——————
Converting form C to F > (F-32)*5/9Understand it better if we have Fahrenheit just add to the equation mentioned to find Celsius.
+to find F to C> (9/5*C)+32

•425 Fahrenheit = (425- 32) × 5/9 =218.33333333 Celsius

•1935 C = 3515 F
———————————-
Converting Celsius to kelvin,We know that :
K = C + 273.15
C = K - 273.15
And from F to K=9/5(F+459.67)
And K to F =(9/5 *k)-459.67
•39.4 Celsius = 312.55 kelvin
•337 Fahrenheit = (337+ 459.67) × 5/9 =442.594 kelvin





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Read 2 more answers
How many moles of methane (CH4) is<br> 6.70 x 1022 atoms of methane?
suter [353]

Answer:

0.1113  mol

Explanation:

Data Given:

no. of atoms of CH₄= 6.70 x 10²² atoms

no. of moles of methane (CH₄) = ?

Solution:

we will find no. of moles of methane (CH₄)

Formula used

          no. of moles = no. of atoms / Avogadro's number

Where

Avogadro's number = 6.022 x 10²³

Put values in above equation

         no. of moles = 6.70 x 10²² atoms / 6.022 x 10²³ (atoms/mol)

         no. of moles = 0.1113  mol

So,

There are 0.1113 moles of methane.

8 0
3 years ago
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