The astronaut then measures the abundance of strontium on the new planet, obtaining the following results:

1 answer:

8 0

Atomic mass is equal to the average number allowing for the relative abundances of different isotopes. It is calculated by:

Atomic mass = ΣzₓAₓ

where zₓ is the relative abundance of the isotope and Aₓ is the atomic mass of the isotope.

Atomic mass = (0.0946x85.91) + (0.07x86.91) + (0.8354x87.91) = 87.6508 amu

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Explain what happens to the energy in a wave when a sound is louder.

liraira [26]

Greater amplitude waves have more energy and greater intensity, so they sound louder. ... The same amount of energy is spread over a greater area, so the intensity and loudness of the sound is less. This explains why even loud sounds fade away as you move farther from the source.

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3 years ago

Draw the lewis structure of ch3nc; fill in any nonbonding electrons. Calculate the formal charge on each atom other than hydroge

jenyasd209 [6]

A visual representation of covalent bonding which represents the valence shell electrons in the molecule is said to be a Lewis structure. The lines represents the shared electron pairs and dots represents the electrons that are not involved in the bonding i.e lone pairs.

Number of valence electrons in each atom:

For Carbon, $C$ = 4

For Hydrogen, $H$ = 1

For Nitrogen, $N$ = 5

The Lewis structure of $CH_3NC$ is shown in the attached image.

The formula of calculating formula charge = $FC = VE - NE- \frac{BE}{2}$ -(1)

where, F.C is formal charge, V.E is number of valence electrons, N.E is number of non-bonding electrons and B.E is number of bonding electrons.

Now, calculating the formal charge:

For $C$ on left side:

$FC = 4 - 0- \frac{8}{2} = 0$

For $N$ :

$FC = 5 - 0- \frac{8}{2} = +1$

For $C$ on right side:

$FC = 4 - 2- \frac{6}{2} = -1$

The formula charge of each atom other than hydrogen is shown in the attached image.

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3 years ago

What is the mass of ca(oh)2 in 110. mL of 1.244 M ca(oh)2 solution

stealth61 [152]

V= 110mL = 110cm³ = 0,11dm³
C = 1,244 mol/L = 1,244 mol/dm³

C = n/V
n = 1,244×0,11
n = 0,13684 moles

mCa(OH)₂ = 74 g/mol

1 mole Ca(OH)₂ ------------ 74g
0,13684 ---------------------- X
X = 74×0,13684
X = 10,12616g

:)

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3 years ago

The fact that HBO2, a reactive compound, was produced rather than the relatively inert B2O3 was a factor in the discontinuation

Reil [10]

Answer:

1027.62 g

Explanation:

For $B_2H_6$ :-