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stich3 [128]
3 years ago
13

CC14 Element Compound Which one is it

Chemistry
1 answer:
wariber [46]3 years ago
7 0
I think the answer is Compound.
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4 0
3 years ago
What is the percent yield of a reaction in which 51.5 g of tungsten(VI) oxide (WO3) reacts with excess hydrogen gas to produce m
Rus_ich [418]

Answer:

The percent yield of a reaction is 48.05%.

Explanation:

WO_3+3H_2\rightarrow W+3H_2O

Volume of water obtained from the reaction , V= 5.76 mL

Mass of water = m = Experimental yield of water

Density of water = d = 1.00 g/mL

M=d\times V = 1.00 g/mL\times 5.76 mL=5.76 g

Theoretical yield of water : T

Moles of tungsten(VI) oxide = \frac{51.5 g}{232 g/mol}=0.2220 mol

According to recation 1 mole of tungsten(VI) oxide gives 3 moles of water, then 0.2220 moles of tungsten(VI) oxide will give:

\frac{3}{1}\times 0.2220 mol=0.6660 mol

Mass of 0.6660 moles of water:

0.666 mol × 18 g/mol = 11.988 g

Theoretical yield of water : T = 11.988 g

To calculate the percentage yield of reaction , we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

=\frac{m}{T}\times 100=\frac{5.76 g}{11.988 g}\times 100=48.05\%

The percent yield of a reaction is 48.05%.

7 0
3 years ago
Read 2 more answers
4 AlF3 + 3 O2 ----------&gt; 2Al2O3 + 6 F2
anyanavicka [17]

Explanation:

6 F2------->4 AlF3

F2-----------> 4/6 AlF3

8.25 F2 ---------> 4×8.25/6 AlF3

so 5.5 moles

8 0
3 years ago
In the reaction below how would adding more of product C affect the equilibrium of the system? A+B arrows both ways C+D
Shalnov [3]

Answer:

1. The reaction will proceed backward, shifting the equilibrium position to the left.

2. The reaction will proceed forward, shifting the equilibrium position to the right.

3. Either add more of the products ( H2O or Cl2) or remove the reactant (HCl or O2)

Explanation:

3 0
3 years ago
What is the scientific name of water<br>​
spayn [35]

Answer:

Dihydrogen monoxide is one of the scientific names of water having the formula H2O, where H2 "dihydrogen" is a double hydrogen (Latin Hydrogenium — hydrogen), and O is "monoxide" (oxygen).

5 0
3 years ago
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