Explanation:
The given reaction equation will be as follows.
![[FeSCN^{2+}] \rightleftharpoons [Fe^{3+}] + [SCN^{-}]](https://tex.z-dn.net/?f=%5BFeSCN%5E%7B2%2B%7D%5D%20%5Crightleftharpoons%20%5BFe%5E%7B3%2B%7D%5D%20%2B%20%5BSCN%5E%7B-%7D%5D)
Let is assume that at equilibrium the concentrations of given species are as follows.
M
M
M
Now, first calculate the value of
as follows.
![K_{eq} = \frac{[Fe^{3+}][SCN^{-}]}{[FeSCN^{2+}]}](https://tex.z-dn.net/?f=K_%7Beq%7D%20%3D%20%5Cfrac%7B%5BFe%5E%7B3%2B%7D%5D%5BSCN%5E%7B-%7D%5D%7D%7B%5BFeSCN%5E%7B2%2B%7D%5D%7D)
= 
= 
Now, according to the concentration values at the re-established equilibrium the value for
will be calculated as follows.
![K_{eq} = \frac{[Fe^{3+}][SCN^{-}]}{[FeSCN^{2+}]}](https://tex.z-dn.net/?f=K_%7Beq%7D%20%3D%20%5Cfrac%7B%5BFe%5E%7B3%2B%7D%5D%5BSCN%5E%7B-%7D%5D%7D%7B%5BFeSCN%5E%7B2%2B%7D%5D%7D)
M
Thus, we can conclude that the concentration of
in the new equilibrium mixture is
M.
Answer:
the electricity dissipated, because of the time.
Explanation:
electricity dissipates.
Answer:
The volume will be 89.6875 ml
Explanation:
So to count this we will use a single proportion.
0.0640 mol - 1000 ml
5.74×10−3 mol - x ml
x ml=5.74×10−3 mol*1000 ml/0.0640 mol=89.6875 ml
D) because both reactions are occurring at the same rate. They are not equal but their concentrations are constant.
Answer:
The entropy and the systems surrounding it tend to increase.