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irina1246 [14]
4 years ago
6

Write the Lewis structure and molecular formula for each of the following hydrocarbons:

Chemistry
1 answer:
dusya [7]4 years ago
4 0

Answer:

molecular formula:

a) Hexane: C6H14

b) 3-methylpentane: C6H14

c) cis-3-hexene: C6H12

d)4-methyl-1-pentene: C6H12

e) 3-hexyne: C6H10

f) 4-methyl-2-pentyne: C6H10

Explanation:

structure:

a) hexane : CH3-CH2-CH2-CH2-CH2-CH3

b) 3-metilpentane: CH3-CH2-CH-CH3-CH3

                                                 CH3

c) cis-3-hexene:   CH3-CH2-CH=CH-CH2-CH3

d)4-methyl-1-pentene: CH2=CH-CH2-CH-CH3

                                                              CH3

e) 3-hexyne: CH3-CH2-C≡C-CH2-CH3

f)4-methyl-2-pentyne: CH3-C≡C-CH-CH3

                                                      CH3

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Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 9.32 g of ethane is
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Answer:

There will remain 8.06 grams of ethane

Explanation:

Step 1: Data given

Mass of ethane = 9.32 grams

Mass of oxygen = 12.0 grams

Molar mass ethane = 30.07 g/mol

Molar mass oxygen = 32.00 g/mol

Step 2: The balanced equation

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Step 3: Calculate moles ethane

Moles ethane = mass ethane / molar mass ethane

Moles ethane = 9.32 grams / 30.07 g/mol

Moles ethane = 0.3099 moles

Step 4: Calculate moles oxygen

Moles oxygen = 12.0 grams / 32.0 g/mol

Moles oxygen = 0.375 moles

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For 2 moles ethane we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2O

O2 is the limiting reactant. It will completely be consumed ( 0.375 moles)

Ethane is in excess. There will react 2/7 * 0.375 = 0.107 moles

There will remain 0.375 - 0.107 = 0.268 moles

Step 6: Calculate mass ethane

Mass ethane = moles ethane * molar mass ethane

Mass ethane = 0.268 moles * 30.07 g/mol

Mass ethane = 8.06 grams

There will remain 8.06 grams of ethane

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Complete Question:

check the first image for complete part of the question

Answer and Explanation:

Epoxide is a three membered ring made up of two carbon atoms and one oxygen atom. Epoxides are cyclic ethers. Due to its ring size, it is highly strained and very reactive. Epoxide ring opening takes place with respect to addition of acid and base.

Ring opening of epoxide with acid:  

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Ring opening of epoxide with base:  

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(check file 2 attached)

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