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4 years ago

Write the Lewis structure and molecular formula for each of the following hydrocarbons:

Chemistry

1 answer:

dusya [7]4 years ago

4 0

Answer:

molecular formula:

a) Hexane: C6H14

b) 3-methylpentane: C6H14

c) cis-3-hexene: C6H12

d)4-methyl-1-pentene: C6H12

e) 3-hexyne: C6H10

f) 4-methyl-2-pentyne: C6H10

Explanation:

structure:

a) hexane : CH3-CH2-CH2-CH2-CH2-CH3

b) 3-metilpentane: CH3-CH2-CH-CH3-CH3

CH3

c) cis-3-hexene: CH3-CH2-CH=CH-CH2-CH3

d)4-methyl-1-pentene: CH2=CH-CH2-CH-CH3

CH3

e) 3-hexyne: CH3-CH2-C≡C-CH2-CH3

f)4-methyl-2-pentyne: CH3-C≡C-CH-CH3

CH3

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Plz help... answer this question!

Mkey [24]

Answer:

Explanation:

Because element is made up of only one type of atoms and figure b show only one type of atoms.

5 0

3 years ago

Which set of changes does not involve breaking or forming chemilcal bonds

sineoko [7]

<h2><u>Answer:</u></h2>

It wasn't an adjustment in the condition of issue on the grounds that the vitality in the can did not change. Additionally, since this was a physical change, the atoms in the can are as yet similar particles. No synthetic bonds were made or broken. You added enough vitality to make a stage change from strong to fluid.

The main changes recorded which don't include framing or breaking substance bonds would bubble and liquefying. Bubbling and liquefying are physical changes as opposed to synthetic changes, so no new items are shaped.

6 0

3 years ago

All elements have a AHf, of ___

stellarik [79]

All elements have a AHf, of <u>0</u>

kJ/mole at standard temperature and pressure.

<h3>What is an element?</h3>

An element can be defined as a substance which cannot be split into two or more simpler forms by an ordinary chemical process

Below are the list of the first twenty elements:

Hydrogen
Helium
Lithium
Berylium
Boron
Carbon
Nitrogen
Oxygen
Fluorine
Neon
Sodium
Magnesium
Aluminum
Silicon
Phosphorus
Sulphur
Chlorine
Argon
Potassium
Calcium

So therefore, all elements have a AHf, of <u>0</u>

kJ/mole at standard temperature and pressure.

Learn more about elements:

brainly.com/question/11829854

#SPJ1

7 0

2 years ago

The following ionization energies were found for an unknown element: -

Alika [10]

Answer:

The common ion will be di-positive ion.

Explanation:

The ionization energy is defined as the amount of energy needed for removal of most loosely bound electron from an isolated atom in gaseous state.

The low ionization energy shows that the atom is able to give electron easily as after losing electron it may attain noble gas configuration or half filled stability.

Here the first and second ionization energy, both are low suggesting that the element is ready to give two electrons easily to form a di-positive ion however the third ionization energy is high which shows that it will not form tri-positive ion commonly.

7 0

3 years ago

Select correct examples of linear molecules for five electron groups. Select correct examples of linear molecules for five elect

Shalnov [3]

Explanation:

Formula to calculate hybridization is as follows.

Hybridization = $\frac{1}{2}[V+N-C+A]$

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

So, hybridization of $BeCl_{2}$ is as follows.

Hybridization = $\frac{1}{2}[V + N - C + A]$

= $\frac{1}{2}[2 + 2]$

= 2

Hybridization of $BeCl_{2}$ is sp. Therefore, $BeCl_{2}$ is a linear molecule. There will be only two electron groups through which Be is attached.

Similarly, hybridization of $XeF_{2}$ is calculated as follows.

Hybridization = $\frac{1}{2}[V + N - C + A]$

= $\frac{1}{2}[8 + 2]$

= 5

Therefore, hybridization of $XeF_{2}$ is $sp^{3}d. Therefore, [tex]XeF_{2}$ is also a linear molecule. Though there are three lone pair of electrons present on a xenon atom and it is further attached with fluorine atoms through two electron pairs. Hence, there are in total five electron groups.

Thus, we can conclude that out of the given options $XeF_{2}$ is the correct examples of linear molecules for five electron groups.

7 0

3 years ago