Answer:
C. (-3,11)
Step-by-step explanation:
Tp is (-3,6) implies the quadratic could have been
f(x) = (x+3)²+6
(2/3)f(x) = (2/3)[(x+3)²+6]
= (2/3)(x+3)²+4
(2/3)f(x)+3 = (2/3)(x+3)²+4+3
= (2/3)(x+3)²+7
Tp at (-3,7)
Alternately,
No change in domain so x remains-3
(2/3)f(x) changes y from 6 to 4 (6×2/3)
+3 increases the y by 3
i.e 4+3 = 7
So, (-3,7)
Answer:
2.) 0.10 (3.) 0.10 (4.) 2.43
Step-by-step explanation:
Given that:
x p(x)
0 0.12
1 0.18
2 0.30
3 0.15
4
5 0.10
6 0.05
X : __0__ 1 ___ 2 ___ 3 _____ 4 ____ 5 ____ 6
p(x):0.12_0.18_0.30_0.15__0.10___0.10 ___0.05
Σ of p(x) = 1
(0.12 + 0.18 + 0.30 + 0.15 + x + 0.10 + 0.05) = 1
0.9 + x = 1
x = 1 - 0.9
x = 0.1
2.)
P(x = 4) = 0.10
3.)
P(x = 5) = 0.10
4.)
Σ(x * p(x)) :
(0*0.12) + (1*0.18) + (2*0.3) + (3*0.15) + (4*0.1) + (5*0.1) + (6*0.05) = 2.43
So this question you just add..... but this is irrational because it does not terminate meaning the decimal doesnt end home this helped have an amazing day!
1,431 pounds to go all the way around Wilmas house
