PLS HELP!! ASAP!!!!!

A bag contains 13 pieces of candy. In how many ways can five pieces be selected?

Whitepunk [10]

Five pieces can be selected in 1287 ways

Step-by-step explanation:

When the selection has to be made without considering the order of selection, combinations are used.

The formula for combination is:

$C(n,r) = \frac{n!}{r!(n-r)!}$

Here

Total candies = n = 13

Candies to be selected = r = 5

Putting the values in the formula

$C(13,5) = \frac{13!}{5!(13-5)!}\\=\frac{13!}{5!8!}\\=1287\ ways$

Five pieces can be selected in 1287 ways

Keywords: Combinations, selection

Learn more about combinations at:

#LearnwithBrainly

3 0

3 years ago

What is the value of the expression below when y = 7? 2y^2 + 9y + 2 Help me!!!!!

Flauer [41]

Answer:

163

Step-by-step explanation:

$2*(7^{2}) +9(7)+2$

$2*(49)+9(7)+2$

$98+63+2$

$=163$

8 0

4 years ago

A line passes through the point -10,9 and has a slope of 1/2. Write an equation in slope-intercept form for this line

vitfil [10]

Answer:

Step-by-step explanation:

The slope intercept form of an equation of a line is y = mx + b, where m is the slope and b is the y-intercept (the value of y when x=0).

Since the slope is (1/2), we can write:

y = (1/2)x + b

We want a value of b such that it forces the line to go through point (-10,9). Enter that point in the equation and solve for b:

y = (1/2)x + b

9 = (1/2)*(-10) + b

9 = -5 + b

b = 14

The eqyuation of a line with a slope of (1/2) and goes through point (-10,9) is:

y = (1/2)x + 14

See attachment.

7 0

3 years ago

What is the interquartile range

motikmotik

Answer:

Step-by-step explanation:

Khan academy huh?

put the numbers in order from least to greatest.
find the median
find the difference between the median and all of the other numbers.

P.S. If you were looking for somebody to tell you the answer don't hold your breath.

8 0

4 years ago

A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang

laiz [17]

Answer-

a. Probability that three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

Solution-

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

$\binom{19}{3} = \frac{19!}{3!16!} = 969$

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

$\binom{33}{6} = \frac{33!}{6!27!} =1107568$

So total number of selection = (969)×(1107568) = 1073233392

Drawing 9 candies out of 52 candies,

$\binom{52}{9} = \frac{52!}{9!43!} = 3679075400$

∴P(3 white candies) = $\frac{1073233392}{3679075400} =0.29$

Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

$\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}$

$=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})$

$=(969)(45)(7)(5)(15)=22892625$

Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,

$\binom{52}{9}=\frac{52!}{9!43!} =3679075400$

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

$\frac{22892625}{3679075400} = 0.006$

6 0

4 years ago