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vladimir2022 [97]
2 years ago
15

What is chemicle reaction

Chemistry
1 answer:
notka56 [123]2 years ago
5 0

Answer:

a process that involves rearrangement of the molecular or ionic structure of a substance as distinct from a change in physical form or a nuclear reaction

Explanation:

please mark brainlest

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What is the atomic number of a sodium atom that has 11 protons and 12 neutrons?
galben [10]
Answer should be 23.
3 0
3 years ago
0.5 moles of sodium chloride is dissolved to make 0.05 liters of solution what is the molarity
Sunny_sXe [5.5K]
Molarity =  moles of solute / liters of solution

M = 0.5 / 0.05

M = 10.0 mol/L⁻¹

hope this helps!
4 0
3 years ago
What is Gibbs free energy
Alenkinab [10]

Answer:

The minimum amount of energy needed the the cell to perform various cellular,biochemical and physiological activities is known is Gibbs free energy.

Explanation:

The change in gibbs free energy of is very much important to determine whether a given reaction is spontaneous,non spontaneous  or equilibrium.

 1 If gibbs free energy change of a reaction is negative then the reaction is spontaneous.

2  If the free energy change is 0 then the reaction is in equilibrium stage.

3  If free energy change is positive then the reaction is non spontaneous.

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3 years ago
Which material has a density most similar to the density of water?
konstantin123 [22]

Answer:

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8 0
3 years ago
___CH4 + ___O2 → ___CO2 + ___H2O When you burn natural gas in the laboratory, methane burns. What numbers fill in the blanks to
Hitman42 [59]

Answer:

The coefficient are 1,2,1,2 ( option B is correct)

Explanation:

Step 1: Data given

Methane = CH4

Burning methane = CH4 + O2

Step 2: The unbalanced equation

CH4(g) + O2(g) → CO2(g) + H2O(g)

Step 3: Balancing the equation

CH4(g) + O2(g) → CO2(g) + H2O(g)

On the left side we have 4x H (in CH4), on the right side we have 2x H (in H2O). To balance the amount of H, on both sides, we have to multiply H2O (on the right side by 2).

CH4(g) + O2(g) → CO2(g) + 2H2O(g)

On the left side we have 2x O (in O2), on the right side we have 4x O (2x in CO2 and 2x in 2H2O). To balance the amount of O on both sides, we have to multiply O2 (on the left side by 2).

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

The coefficient are 1,2,1,2 ( option B is correct)

3 0
3 years ago
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