Ask question

Ask question

All categories

vladimir2022 [97]

2 years ago

15

What is chemicle reaction

1 answer:

notka56 [123]2 years ago

5 0

Answer:

a process that involves rearrangement of the molecular or ionic structure of a substance as distinct from a change in physical form or a nuclear reaction

Explanation:

please mark brainlest

You might be interested in

On the periodic table, the majority of elements are classified as

Roman55 [17]

<span>On the periodic table, the majority of elements are classified as "Metals"

In short, Your Answer would be Option A

Hope this helps!</span>

8 0

3 years ago

Read 2 more answers

The analogy that forms the basis of the octet rule compares covalent valence

o-na [289]

Answer:

b

Explanation:

orbital overlap electron densities.

3 0

3 years ago

Read 2 more answers

A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a

Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = $\frac{x}{100}$

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = $\frac{10}{100}$

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] % = (90 - x) %

Fractional abundance of middle-weight isotope = $\frac{(90-x)}{100}$

Now put all the given values in above formula, we get:

$48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]$

$x=78\%$

Therefore, the percent abundance of the heaviest isotope is, 78 %

5 0

3 years ago

Read 2 more answers

What kind of scientist would study the the first of a car running

iVinArrow [24]

Answer:

A physicist

Explanation:

hope this will help you

7 0

3 years ago

Explain what would happen in Step 2 if the cylinder were heated with the plunger held steady.

Svetradugi [14.3K]

Answer:

be more descriptive

Explanation:

4 0

3 years ago