I believe the answer to this is A.
Answer:
9g
Explanation:
Since..., Density = mass/volume
;Firstly calculate the volume change of the water when the metal is placed in,
;Volume = 26.47 - 21.25
;Volume = 5.22 mL
Hence the mass of the ore;
; Making mass the subject of formula in the above equation,
Mass = Density × Volume
; Mass = 1.72 × 5.22
; Hence the mass = 8.9784
= 9g
Answer:
125000
Explanation:
Because it is halved and halved again.
Answer:
It will be reported too low.
Explanation:
To measure the specific heat of the metal (s), the calorimeter may be used. In it, the metal will exchange heat with the water, and they will reach thermal equilibrium. Because it can be considered an isolated system (there're aren't dissipations) the total amount of heat (lost by metal + gained by water) must be 0.
Qmetal + Qwater = 0
Qmetal = -Qwater
The heat is the mass multiplied by the specific heat multiplied by the temperature change. If c is the specific heat of the water:
m_metal*s*ΔT_metal = - m_water *c*ΔT_water
s = -m_water *c*ΔT_water / m_metal*ΔT_metal
So, if m_water is now less than it was supposed to be, s will be reported too low, because they are directly proportional.
