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3 years ago

Correct answer will receive a Brainliest.

Physics

2 answers:

Gre4nikov [31]3 years ago

8 0

The answer would be c

san4es73 [151]3 years ago

4 0

Answer:

Explanation:

The period of a pendulum is found by the equation: T = 2pi*sqrt(L/g). Let the original length be L and the original period be T. The length increased by a factor of 4, so it’s new length is 4L. We get that the new period is 2pi*sqrt(4L/g) = 2pi*2sqrt(L/g) = 4pi*sqrt(L/g). We can see that the period increased by a factor of 2 because the original period, T, equals 2pi*sqrt(L/g) and the new period is 4pi*sqrt(L/g) = 2(2pi*sqrt(L/g)) = 2T. Therefore, the new period is 2(1.4) = 2.8

I hope this helps! :)

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Anon25 [30]

Total distance moved by bead is 1.952 cm.

Explanation:

Let first consider all data that are given in question.

1. F = 8 N ...force acting on string

2. f = 2 Hz ...frequency of system

3. β = 4 cm = 0.04 m ...wavelength of wave formed due to vibration 4. A = 1 cm = 0.01 m ...Amplitude of vibration

Under certain conditions, waves can bounce back and forth through a particular region, effectively becoming stationary. These are called standing waves.

Here,it is due to vibration induced in spring due to tension induced in string

Standing wave equation is given by

$y = (x,t) = 2A * sinK x * cos (wt)$ ...(1)

Let first find, value of K, x, w, t

k = 2 * pi / beta ....(2)

Where β is wavelength in meters

K is wave number

k = 2 * pi / 0.01

k = 628.31 $m^{-1}$

now, let us find value of w

W = 2 x pi x f ....(3)

where f is frequency in hertz

W = 2 x pi x 2

W = 4 x pi

W = 0.08 $\frac{m}{s}$

$y = (x,t) = 2A * sinK x * cos (wt)$

now, let us find value of v that is wave speed

Notice that some x-positions of the resultant wave are always zero no matter what the phase relationship is. These positions are called nodes.

Finding the positions where the sine function equals zero provides the positions of the nodes.

In our case, and

K * x = pi

x = 0.04 / 2

x = 0.02

$y = (0.02,1) = 2(0.01) * sin pi * cos (12.5664 * 1)$

$y = (0.02,1) = 2(0.01) * -1 * cos 0.9761$

Y = 1.952 cm

Finally, when bead is at middle of the string, total distance after stretch covered is 1.952 cm.

3 0

3 years ago

A force of 20 newtons is exerted on a chair from its right and a force of 12 newtons is applied from

tankabanditka [31]

Answer:

The net force acting on the chair is 8 newtons, and the chair moves toward the left.

Explanation:

We can better understand this problem if we analyze it through a free body diagram. This free body diagram is attached as an image.

If we make a sum of forces acting over the chair we can find -20 + 12 = -8 [N]

The minus sign indicates that the chair is moving to the left.

5 0

3 years ago

You are standing on a skateboard, initially at rest. a friend throws a very heavy ball towards you. you can either catch the obj

PIT_PIT [208]

<span>You should deflect the ball in order to maximize your speed on the skateboard.

Since this creates a larger impulse, you want to deflect the ball. Splitting it up into catching and throwing the ball may by something you can think of deflecting the ball. First, you need to catch the ball, which in turn would push you forward with some speed. (The speed we are talking about should obviously be equal to option A, where you catch the ball). Now, throw the ball back to him since these two processes are equal to deflecting the ball. Throwing a mass away from you would cause or enable you to move even fast.</span>

7 0

3 years ago

A string is wrapped around a pulley with a radius of 2.0 cm. The pulley is initially at rest. A constant force of 50 N is applie

Ray Of Light [21]

Answer:

0.20kg-m^2

Explanation:

Let the linear velocity of the rope(=of pulley) is v m/s

Using kinematic equation

=> v = u + at

=>v = 0 + 4.9a

=>v = 4.9a ------------ eq1

By v^2 = u^2 + 2as

=>v^2 = 0 + 2 x v/4.9 x 1.2

=>4.9v^2 - 2.4v = 0

=>v(4.9v - 2.4) = 0

=>v = 2.4/4.9 = 0.49 m/s

Thus by v = r x omega

=>omega = v/r = 0.49/0.02 = 24.49 rad/sec

BY W = F x s = 50 x 1.2 = 60 J

=>KE(rotational) = W = 1/2 x I x omega^2

=>60 = 1/2 x I x (24.49)^2

=>I = 0.20 kg-m^2

5 0

3 years ago

Single Replacement: HCI + Zn

Kay [80]

During a single replacement, the Zn and H will switch places. That means the product formed will be ZnCl and H2.

4 0

3 years ago