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defon
3 years ago
10

3.5-m-diameter merry-go-round is rotating freely with an angular velocity of 0.78 rad/s . Its total moment of inertia is 1710 kg

⋅m2 . Four people standing on the ground, each of mass 66 kg , suddenly step onto the edge of the merry-go-round.
A. What is the angular velocity of the merry-go-round now?
B. What if the people were on it initially and then jumped off in a radial direction (relative to the merry-go-round)?
Physics
1 answer:
Monica [59]3 years ago
4 0
I dont get the question your asking
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Explanation:

Given

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As Energy is conserved therefore Energy at top is equal to energy at bottom

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\frac{mv^2}{2}+mgh=\frac{mv_0^2}{2}  ,where v_0 is the velocity at bottom

\frac{v^2}{2}+gh=\frac{v_0^2}{2}

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v^2=v_0^2-2gh

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7 0
3 years ago
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Answer:

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